Why Is Weight Always Considered Positive?

In summary, the force of weight is always positive because it is a vector with positive magnitude. The sign of its components depends on the chosen coordinate system. In some cases, such as in solid state physics, the effective mass of particles may be opposite to that of the missing particles, but this is not relevant to the question at hand. When solving problems involving projectiles or elevators, it is important to clearly define the direction of components and their corresponding signs. In the case of upward components, a negative change in velocity would result in a downward acceleration, and vice versa. The choice of positive and negative directions can lead to a positive or negative value for g in weight problems.
  • #1
logan3
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I don't understand why the force of weight is always positive. Doesn't gravity point down, so isn't a = g = -9.8 m/s2? I understand that people always say it's because you can choose the positive and negative directions, but why change g to be positive in these weight situations and not in others?

Also, I'm really having trouble understanding this in elevator/scale problems, like when an elevator is moving up, but slowing down.
 
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  • #2
logan3 said:
I don't understand why the force of weight is always positive.
Force is a vector. It's magnitude is always positive. The sign of it's components depends on the chosen coordinates.

logan3 said:
Also, I'm really having trouble understanding this in elevator/scale problems, like when an elevator is moving up, but slowing down.
What don't you understand about a elevator moving up while slowing down?
 
  • #3
Hi.
Bubbles in water have negative mass in contrast to environment, the filled water. Bubble go upward inverse to gravity. It is a funny interpretation, isn't it?
 
  • #4
sweet springs said:
Hi.
Bubbles in water have negative mass in contrast to environment, the filled water. Bubble go upward inverse to gravity. It is a funny interpretation, isn't it?

No, it's sadly an incorrect one.

What do you mean by "Bubbles in water have a negative mass in contrast to environment, the filled water."?

A bubble is a bit of gas which has become trapped temporarily in a surrounding mass of fluid. The bubble rises because its mass is less than that of the volume of water which is displaced by the bubble. Ever hear of this guy Archimedes? It's the principle of buoyancy at work here, not some unicorn called 'negative mass'.
 
  • #5
logan3 said:
I don't understand why the force of weight is always positive.
You are making a good point. There is a choice of coordinate systems but they should all be right hand rule coordinate systems.

Example 1: There are a lot of cases where people use a "North, West, Up" coordinate system to identify positions. There are other cases where "North, East, Down" is used. So "Up" can be either positive or negative, depending on what the coordinate system is.

Example 2: In airplane flight dynamics, the usual body coordinate system is "nose, right wing, down". So "down" is positive. On the other hand, positions on the airplane are usually "tail, right wing, up" (the terminology is "fuselage station, butt line, water line"). In those coordinates, "up" is positive.

The value of 'g' is always stated as positive, but a negative sign must appear somewhere in the equations when needed. So the force of weight can be positive or negative, depending on the coordinate system being used. When you are working on a project, half the work is in keeping track of what mixture of coordinate systems is being used and converting from one to another.
 
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  • #6
SteamKing said:
No, it's sadly an incorrect one.

What do you mean by "Bubbles in water have a negative mass in contrast to environment, the filled water."?

A bubble is a bit of gas which has become trapped temporarily in a surrounding mass of fluid. The bubble rises because its mass is less than that of the volume of water which is displaced by the bubble. Ever hear of this guy Archimedes? It's the principle of buoyancy at work here, not some unicorn called 'negative mass'.
I don't think the example is so bad. E.g. in solid state physics it is customary to consider the holes as particles on it's own which obviously have an effective mass opposite to that of the particles that are missing.
 
  • #7
DrDu said:
I don't think the example is so bad. E.g. in solid state physics it is customary to consider the holes as particles on it's own which obviously have an effective mass opposite to that of the particles that are missing.
It's a terrible example in the context of OP's question. The people who use this trick in solid state physics are already years past learning basic Newtonian mechanics; bringing it up in a thread in started by someone asking why weight is always positive can only lead to confusion.
 
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  • #8
In addition, the holes in a Fermi sea treated as quasi particles in many-body quantum theory (which is quantum field theory in fact) have a positive mass as it should be ;-)).
 
  • #9
logan3 said:
I don't understand why the force of weight is always positive. Doesn't gravity point down, so isn't a = g = -9.8 m/s2? I understand that people always say it's because you can choose the positive and negative directions, but why change g to be positive in these weight situations and not in others?

When you answer questions about projectiles and so on, you should always state in which direction you are taking components. If you choose upwards for one of the components, then g is negative; if you choose downwards, g is positive. If you wish to work with the vector rather than its component, then you use a special symbol like g or [itex]\vec{g}[/itex].

logan3 said:
Also, I'm really having trouble understanding this in elevator/scale problems, like when an elevator is moving up, but slowing down.

Let's deal with upward components of vectors. Then the lift's velocity (component), v, is positive but [itex]\frac{dv}{dt}[/itex] is negative if the lift is slowing down. Thus the upward acceleration component is negative. In fact we could deal directly with the vectors themselves and say that the velocity is upwards but the acceleration is downwards. The latter is true because the change in velocity (final velocity – initial velocity) is downwards.
 
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  • #10
Ok, so I am correct in thinking that if I do the normal thing and have down be negative direction and up be positive, then g in weight problems would be negative, and thus weight would be given as a negative force? But the only reason the force of weight is positive in so many problems is because they choose down to be positive and thus g becomes positive?
 
  • #11
DrDu said:
I don't think the example is so bad. E.g. in solid state physics it is customary to consider the holes as particles on it's own which obviously have an effective mass opposite to that of the particles that are missing.
It's interesting, but I have to disagree for this reason: There is a clear way to set the value of 0 weight. When there are no other massive bodies around, that is 0 weight. In most usage on earth, weight is directly associated with mass. Breaking that relationship would be confusing. A gallon bucket of water under water would "weigh" nothing. Pulled half way out, it would "weigh" 4.17 lb. Pulled completely out of water, it would weigh 8.34 lb. That is one of the signs of the Apocalypse. oo)
 
  • #12
But the only reason the force of weight is positive in so many problems is because they choose down to be positive and thus g becomes positive?

Exactly so.

Though, as pointed out earlier, to be strictly correct, weight itself is a vector so has a direction, but is neither positive nor negative. It's the upward component of weight which is negative, and/or the downward component which is positive.
 
  • #13
logan3 said:
Ok, so I am correct in thinking that if I do the normal thing and have down be negative direction and up be positive, then g in weight problems would be negative, and thus weight would be given as a negative force? But the only reason the force of weight is positive in so many problems is because they choose down to be positive and thus g becomes positive?
I think that you have to be careful about what the variable "g" is referring to in a given context. More specifically, you need to know the type of mathematical object: vector, magnitude, or component.

If g is a magnitude, specifically the constant 9.8 m/s^2, then it is always positive. I think that this is the most common meaning.

If g is a vector then there is no such thing as positive or negative. It points down, but vectors don't have a "greater than" operation, so you cannot say that a vector is greater than 0 or not, so pointing down does not imply that it is negative.

If g is the component of a vector then it can be positive or negative depending on your coordinate system.
 
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  • #14
DaleSpam said:
If g is a vector then there is no such thing as positive or negative. It points down, but vectors don't have a "greater than" operation, so you cannot say that a vector is greater than 0 or not, so pointing down does not imply that it is negative.
Sorry, I don't understand this. A vector has magnitude and direction. The direction denotes whether it is positive or negative.
 
  • #15
logan3 said:
Sorry, I don't understand this. A vector has magnitude and direction. The direction denotes whether it is positive or negative.
No, the direction determines which components of the vector are positive or negative. The vector as a whole doesn't have a sign.
 
  • #16
logan3 said:
Sorry, I don't understand this. A vector has magnitude and direction. The direction denotes whether it is positive or negative.

Force [tex]\mathbf{F}[/tex] is equal to product of weight or mass m and gravity acceleration [tex]\mathbf{g}[/tex]. So [tex]\mathbf{F}=m \mathbf{g}[/tex]. This relation holds for any axis you choose, upward, downward, even perpendicular, etc. When you choose upward axis [tex]\mathbf{g}[/tex] is expressed as negative coordinate. When you choose downward axis [tex]\mathbf{g}[/tex] is expressed as positive coordinate. When you choose perpendicular axis, it is expressed as a pair of coordinates. Vectors [tex]\mathbf{F}[/tex] and [tex]\mathbf{g}[/tex]
have same direction because m is positive number.
 
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  • #17
I think I'm just getting more confused from this thread. People are all saying different things. Thanks anyways.
 
  • #18
logan3 said:
Sorry, I don't understand this. A vector has magnitude and direction. The direction denotes whether it is positive or negative.
No, it doesn't. Is southeast positive or negative?

Vector spaces are not ordered sets.
 
  • #19
logan3 said:
I think I'm just getting more confused from this thread. People are all saying different things. Thanks anyways.
Sorry. I hope you have not given up. Maybe we can start back at the beginning.
logan3 said:
I don't understand why the force of weight is always positive.
It isn't. Always put things in terms of the coordinate system you are using. If the coordinate system you are using says that the direction down is positive, then the downward force of weight is positive. If the coordinate system you are using says that the direction up is positive, then the downward force of weight is negative.
Doesn't gravity point down, so isn't a = g = -9.8 m/s2?
Most people will define g as the positive number 9.8 m/s2. Then, when acceleration is calculated, the equation depends on whether positive direction is down or up. If the coordinate system says that down is positive then downward acceleration from gravity is positive and a = g. But if the coordinate system says that direction up is positive then the downward acceleration from gravity is negative and a = -g.
I understand that people always say it's because you can choose the positive and negative directions, but why change g to be positive in these weight situations and not in others?
I would think of g as always being a positive number 9.8m/s2. It is used with or without a negative sign, as appropriate.for the coordinate system you are using. Either a=g or a=-g, depending on if you are using a coordinate system where down is positive or down is negative, respectively.

Also, I'm really having trouble understanding this in elevator/scale problems, like when an elevator is moving up, but slowing down.
Always put things in terms of the coordinate system that you are using.
Suppose you are using a coordinate system where the direction down is positive. The elevator moving up means that its velocity is negative. The fact that it is slowing down means that its acceleration is positive.

Alternatively, suppose you are using a coordinate system where the direction up is positive. The elevator moving up means that its velocity is positive. The fact that it is slowing down means that its acceleration is negative.
 

FAQ: Why Is Weight Always Considered Positive?

Why can't weight be negative?

Weight is a measure of the force of gravity acting on an object. Since gravity is always directed towards the center of the Earth, weight is always a positive value. Therefore, weight cannot be negative.

Can weight ever be negative?

No, weight can never be negative. As mentioned earlier, weight is a measure of the force of gravity, which is always directed towards the center of the Earth. Therefore, weight will always be a positive value.

What happens if weight is negative?

Since weight cannot be negative, this question is not applicable. However, if we are talking about perceived weight (the feeling of how heavy an object is), a negative value would indicate that the object is being lifted upwards with a force greater than its own weight, making it feel lighter.

Are there any exceptions where weight can be negative?

No, there are no exceptions where weight can be negative. Weight is a physical quantity that is always a positive value, as it is a measure of the force of gravity.

Why do we use positive values for weight instead of negative?

Using positive values for weight makes it easier to compare and calculate the weight of different objects. It also aligns with the laws of physics, as weight is a result of the force of gravity, which is always a positive value. Additionally, using negative values for weight could lead to confusion and errors in calculations.

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