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I hardly interested in using group theory in physics. So higgs boson or spontaneously broken symmetry in my mind add nothing to my physical essence of the processes. Usually i ask myself: what will happen, if we have no symmetry from the beginning and there is no symmetry to be broken?ZapperZ said:The pseudogap in the normal state of the cuprates is not simply a "dielectric gap". The transition at T* is actually a transition to a non-superconducting broken symmetry state. The dielectric gap is simply a gap in the single-particle state.
Next. Is "non-superconducting broken symmetry state" one electron states? I image that it is the one electron states where some states have gap in the direction of the wave vector and some states have no gap in the direction of the wave vector.
Dielectric gap means that all possible states in this direction are busy and the highest in energy level is lower than Fermi energy.
In polar coordinates (direction, pseudogap value) it is 4 petals. If we diminish doping, petals become wider and longer and at some nonzero doping sample can become insulator.
I think superconductor petals and PG petals couldn't overlap for T<Tsc. So you can verify experimentally nonoverlapping.Whether the pseudogap state is a precursor or in competition with superconductivity is still being debated. See R.-H. He et al., Science v.331, p.1579 (2011).
Furthermore, the superconducting gap is not symmetric over the Fermi surface, since it has a d-wave symmetry. The nodal direction has no gap. Your claim that both gaps they are different in different direction needs experimental verification. Zz.
So for underdoped cuprates we can suspect 8 SC petals, for overdoped 4 SC petals. In principle SC petals can themselves overlap and we may have nonzero SC gap in nodal directions.
You are quite right, ZapperZ, that we need more experimental results.
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