- #36
Indranil
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Vavg = 2d / t?jbriggs444 said:No. That's your job.
Vavg = 2d / t?jbriggs444 said:No. That's your job.
Could anyone clarify me please Vavg = 2d / t? I am waiting for the replies.Indranil said:Vavg = 2d / t?
YesIndranil said:t1 + t2 = d / v1 + d / v2, t = d (v1 + v2) / v1v2,
No, in the problem you are considering the total distance is d + d = 2d because you travel distance d from point A to point B and then travel distance d again when you go from point B back to point A.Vavg = d / t
You are complicating the discussion by writing fractions incorrectly. You omit paretheses that are needed.but the equeation is 2v1v2 / v1 + v2
I got it now. I will check myself. please find my faults so that I can improve myself in Physics. I am learning a lot from this site. one more equationStephen Tashi said:YesNo, in the problem you are considering the total distance is d + d = 2d because you travel distance d from point A to point B and then travel distance d again when you go from point B back to point A.You are complicating the discussion by writing fractions incorrectly. You omit paretheses that are needed.
You write "2v1v2/ v1 + v2" when you actually mean "2v1v2/ (v1 + v2)"
Indranil said:one more equation
If t₁ = t₂ = t₃ =...tn, Vav = (v₁ + v₂ +...+ vn)t / nt
What's the concept behind the equation above?
Thank you for your kind advice. I'll try to follow.Stephen Tashi said:The proper format of a physics problem is to have a statement of the problem in words. In that statement, the variables are defined. After the variables are defined in words, equations are written.
You give an equation, but you omit the description of the problem in words and you omit defining the variables.
Many of the homework advisors are capable of seeing an equation and guessing what words describe the problem. However, if you rely on other people to "read your mind", you won't learn to write clearly.
Explain the situation and define the variables that are used.
I don't understand clearly. Could you explain it in detail, please?Nugatory said:You have ##n## time intervals, all equally long. ##t_1## is the length of the first interval, ##t_2## is the length of the second one, and so forth.
If t₁ = t₂ = t₃ =...= tn, Then we have Vavg = (v₁ + v₂ +...+Vn)t / ntIndranil said:Thank you for your kind advice. I'll try to follow.
If t₁ = t₂ = t₃ =...= tn, Then we have Vavg = (v₁ + v₂ +...+Vn)t / nt
What is the concept behind this formula?
Indranil said:If t₁ = t₂ = t₃ =...= tn, Then we have Vavg = (v₁ + v₂ +...+Vn)t / nt
What is the concept behind this formula?
I am waiting for the replies
The concept behind this formula is the same as all the others: Vave = Distance/Time. Of all the formulas you've been asking about, this basic definition of average speed is the one you need to have down cold. All the rest can be derived from this with a little algebra.Indranil said:If t₁ = t₂ = t₃ =...= tn, Then we have Vavg = (v₁ + v₂ +...+Vn)t / nt
What is the concept behind this formula?