Why work done on a system causes heat to flow out of it?

In summary, the compression of a gas can cause heat to flow out of the container, leading to an increase in temperature. This is known as adiabatic compression and does not involve any heat exchange with the environment. However, if the compression is isothermal, an external reservoir is needed to maintain a constant temperature. If no heat is exchanged with the surroundings, the compression will be adiabatic.
  • #1
sycircle
6
0
I don't understand how compression of a gas causes heat to flow out of the container of that gas... Could someone please help? Thank you in advance!
 
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  • #2
Compression heats the gas. If it started at the temperature of the environment, it gets hotter than its environment. What do you expect to happen next?

This has nothing to do with nuclear and particle physics, I moved the thread to classical physics.
 
  • #3
The compression does not have this effect, in general.
You should be more specific in your questions.
Adiabatic compression, for example, happens without any heat exchange between the gas and the environment. The gas just heats up.

You may have in mind isothermal compression.
In this case, in order to ensure the constant temperature condition, the gas needs to be in contact with an external reservoir which will absorb whatever heat is necessary to keep the temperature constant.
If the gas does not give up heat to exterior then it cannot be iso-thermal. It will be adiabatic.
So the heat exchange situation depends on the external conditions, not on the compression itself. .
 

FAQ: Why work done on a system causes heat to flow out of it?

1. What is the relationship between work done on a system and heat flow?

The first law of thermodynamics states that the total energy of a closed system remains constant, meaning that any change in energy must be accounted for by changes in other forms. When work is done on a system, it increases the internal energy of the system. As a result, the system must release an equivalent amount of energy in the form of heat to maintain its total energy.

2. Why does work done on a system cause heat to flow out of it?

Work done on a system involves the transfer of energy to the system, which increases its internal energy. This increase in energy causes the molecules in the system to move faster, resulting in an increase in temperature. In order to maintain equilibrium and conserve energy, the system must release this excess energy in the form of heat, causing it to flow out of the system.

3. How does the direction of heat flow relate to the work done on a system?

The direction of heat flow is always from hotter objects to cooler objects. When work is done on a system, it increases the internal energy and temperature of the system. Heat will naturally flow out of the system to cooler surroundings in order to maintain equilibrium.

4. Can work done on a system result in a decrease in temperature?

Yes, it is possible for work done on a system to result in a decrease in temperature. This can happen if the work done on the system is less than the amount of heat being released. In this case, the system will still lose energy in the form of heat, but the decrease in internal energy and temperature will be less than if no work had been done on the system.

5. How does the type of work affect the amount of heat flow out of a system?

The type of work being done on a system can affect the amount of heat flow out of it. For example, if the work is done slowly and isothermal (at constant temperature), there is minimal increase in internal energy and therefore less heat flow out of the system. On the other hand, if the work is done quickly and adiabatically (without heat transfer), the increase in internal energy will be greater, resulting in a larger amount of heat flowing out of the system to maintain equilibrium.

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