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1MileCrash
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Homework Statement
Wolfram says the derivative of (sin x)^2 is sin2x. Shouldn't it be 2(sin x)(cos x)?
1MileCrash said:Homework Statement
Wolfram says the derivative of (sin x)^2 is sin2x. Shouldn't it be 2(sin x)(cos x)?
Synthetic?1MileCrash said:I like using it for things like vectors, I just don't like the identities. They feel "synthetic."
Wolfram's Derivative of (sin x)^2 is the mathematical expression for finding the derivative of the function (sin x)^2, also known as the derivative function.
Wolfram's Derivative of (sin x)^2 is calculated using the power rule, which states that the derivative of x^n is n*x^(n-1). In this case, the derivative of (sin x)^2 is 2*(sin x)^(2-1) = 2*sin x.
No, Wolfram's Derivative of (sin x)^2 follows the same rules and principles as other derivative formulas. It is simply a specific expression for finding the derivative of (sin x)^2.
The derivative of (sin x)^2 is important because it allows us to calculate the rate of change of the function (sin x)^2 at any given point. This can be useful in many applications, such as physics, engineering, and economics.
Yes, Wolfram's Derivative of (sin x)^2 can be used for any value of x, as long as the function (sin x)^2 is defined at that point. However, the derivative may not exist at certain values of x, such as at x = pi/2, where the function has a vertical tangent line.