Word problem - Application of linear equations

In summary: No, your solution is not correct. The correct solution is:Let x = number of students who passed and are taking English CompositionLet y = number of students who failed and are taking English FundamentalsWe are given:x + y = 1240 (total number of students)y > x (more students are taking English Fundamentals)If 30 more students had passed the test, then:x + 30 = number of students taking English Compositiony - 30 = number of students taking English Fundamentalsx + 30 = y - 30 (each course would have the same enrollment)Solve this system of equations to find:x = 605 (number of students taking English Composition)y =
  • #1
paulmdrdo1
385
0
Every freshman student at a particular college is required to take an english aptitude exam. A student who passes the examination enrolls in english composition, and a student who fails the test must enroll in english fundamentals. In a freshman class of 1240 students there are more students enrolled in english fundamentals than in english composition. However, if 30 more students had passed the test, each course would have the same enrollment. how many students are taking each course?

My solution

let $x=$number of students who passed

$1240-x =$ number of students who failed

$x+30=1240-x$

$2x=1240-30$
$2x=1210$
$x=605$

605 students are taking English Composition
635 students are taking English fundamentals

is my solution correct?

thanks!
 
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  • #2
I would let $P$ be the number who passed and $F$ be the number who failed. We are given in the problem:

\(\displaystyle P+F=1240\)

\(\displaystyle P+30=F-30\)

Note that if we add 30 to those that passed, then we have to subtract 30 from those that failed. So solve this system...what do you find?
 
  • #3
paulmdrdo said:
Every freshman student at a particular college is required to take an english aptitude exam. A student who passes the examination enrolls in english composition, and a student who fails the test must enroll in english fundamentals. In a freshman class of 1240 students there are more students enrolled in english fundamentals than in english composition. However, if 30 more students had passed the test, each course would have the same enrollment. how many students are taking each course?

My solution

let $x=$number of students who passed

$1240-x =$ number of students who failed

$x+30=1240-x$
This is incorrect. "If 30 more students had passed the test" then, yes, the number of students who passed and so must take one course is x+ 30 but then the number who failed, and must take the other course would be 30 less: 1240- (x+ 30)= 1210- x.

The equation you want to solve is x+ 30= 1210- x.
$2x=1240-30$
$2x=1210$
$x=605$

605 students are taking English Composition
635 students are taking English fundamentals

is my solution correct?

thanks!
 

FAQ: Word problem - Application of linear equations

What is a linear equation?

A linear equation is an algebraic equation that represents a straight line when graphed. It contains only variables that are raised to the first power and has a constant term. The general form of a linear equation is y = mx + b, where m is the slope of the line and b is the y-intercept.

How are linear equations used to solve word problems?

Linear equations can be used to solve word problems by representing real-life situations with mathematical equations. This allows us to find the value of a variable, such as time, distance, or cost, by using the given information and solving for the unknown variable.

What are some common applications of linear equations?

Linear equations have many practical applications in fields such as physics, economics, and engineering. Some common examples include calculating speed and distance in a physics problem, determining cost and revenue in business, and finding slopes and intercepts in graphing.

How do you solve a system of linear equations?

A system of linear equations is a set of two or more equations with multiple variables. To solve a system, we use methods such as substitution, elimination, or graphing. These methods involve manipulating the equations to eliminate one variable and solve for the others.

Can linear equations have more than one solution?

Yes, linear equations can have one, zero, or infinitely many solutions. A solution to a linear equation is a value that makes the equation true. If a linear equation has two or more variables, it can have infinitely many solutions, represented by a line on a graph. However, if the equation has only one variable, it can have one or zero solutions, depending on the values of the variables.

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