- #1
NotaMathPerson
- 83
- 0
Hello! I need on these problems
My attempt in prob 38
$x=$ number of candidates failed
$4x=$ number of candidates passed
$5x=$ total number of candidates
From the given scenerio we add 14 more cadidates
$5x+14$
Six less failed
$x-6=$ new number of candidtes failed
$4x+6=$ new number of cadidates passed
Now
$5x+14-(x-6)=$ new number candidates passed
Then
$5x+14-(x-6)=5(x-6)$
Solving for x
$x=50$
Therefore $5x=5*50=250$ candidates.
But when I did the reverese
$5x+14-(4x+6)=$ new number of candidates failed
Then
$4x+6=5(5x+14-(4x+6))$
$4x+6=5(x+8)$
Solving for x gives a different answer.
The first answer agrees with the answer from the book.
Can you tell why I get different answers from the different methods I presented? Thanks much!
My attempt in prob 38
$x=$ number of candidates failed
$4x=$ number of candidates passed
$5x=$ total number of candidates
From the given scenerio we add 14 more cadidates
$5x+14$
Six less failed
$x-6=$ new number of candidtes failed
$4x+6=$ new number of cadidates passed
Now
$5x+14-(x-6)=$ new number candidates passed
Then
$5x+14-(x-6)=5(x-6)$
Solving for x
$x=50$
Therefore $5x=5*50=250$ candidates.
But when I did the reverese
$5x+14-(4x+6)=$ new number of candidates failed
Then
$4x+6=5(5x+14-(4x+6))$
$4x+6=5(x+8)$
Solving for x gives a different answer.
The first answer agrees with the answer from the book.
Can you tell why I get different answers from the different methods I presented? Thanks much!