- #1
paulmdrdo1
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please help me with this problem
please use single variable only.
The length of a rectangular swimming pool is twice its width. The pool is surrounded by a cement walk 4ft wide. If the area of the walk is 748 ft^2, determine the dimensions of the pool.
let x = width of the pool
2x = length of the pool
the dimensions of the pool and cement walk combined
x+8 = width
2x+8 = length
the area of the pool plus the area of the cement walk is equal to the whole area.
$(2x+8)(x+8)=748+2x^2$
$x= 28.5$
the dimensions of the pool is 28.5 ft by 57 ft.
but the answer in my book is 30 ft. by 60 ft. why is that? where did I miss?
regards!
please use one variable only.
please use single variable only.
The length of a rectangular swimming pool is twice its width. The pool is surrounded by a cement walk 4ft wide. If the area of the walk is 748 ft^2, determine the dimensions of the pool.
let x = width of the pool
2x = length of the pool
the dimensions of the pool and cement walk combined
x+8 = width
2x+8 = length
the area of the pool plus the area of the cement walk is equal to the whole area.
$(2x+8)(x+8)=748+2x^2$
$x= 28.5$
the dimensions of the pool is 28.5 ft by 57 ft.
but the answer in my book is 30 ft. by 60 ft. why is that? where did I miss?
regards!
please use one variable only.