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oceanscreams
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Homework Statement
An 80-N box is pulled 20m up a 30 degree incline by an applied force of 115 N that points upward, parallel to the incline. If the coefficient of kinetic friction between box and incline is 0.22, calculate the change in the kinetic energy of the box.
Homework Equations
ΔKE = 1/2mVf2-1/2mVi2 = mghi- mghf
The Attempt at a Solution
This is what i have understood so far, if there's a mistake please help me.
Given:
Fg= 80N so m=8.15kg
hi= 20m
θ= 30°
μk= 0.22
Fapp= 115N
I drew the ramp, and labeled all the forces. Also, I found Fgx to be 40N. My question is, what do they mean by change in KE? Should I find work done? If so, is it Wnet= Fdcosθ ? I'm really confused, I've spent more than an hour looking for solutions online, but I don't understand the explanation and I decided to try asking myself. Please explain what I should do, I've tried solving several times, but I can't seem to find the answer, and I also have a lot of other problems to solve.
Help is appreciated. Thank you