Work done by heat engine that uses exhaust from heat pump

In summary, the work done by a heat engine utilizing exhaust from a heat pump involves converting waste thermal energy into mechanical work. The heat pump extracts heat from a lower temperature source and releases it at a higher temperature, while the heat engine exploits the temperature difference to perform work. This process enhances overall energy efficiency by recycling waste heat, thereby reducing the need for additional energy input and minimizing environmental impact.
  • #1
zenterix
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Homework Statement
Suppose an inventor claims that he/she can do the following.

Using only the heat exhaust from a refrigerator and an unlimited supply of liquid nitrogen, he/she can generate more energy than his refrigerator uses to operate.

The refrigerator is an ideal heat pump that keeps its contents at 275K by pumping out exhaust at 304K.

The inventor uses an ideal heat engine to generate work from the refrigerator's exhaust.

Liquid nitrogen at 75K is used to cool the heat engine.
Relevant Equations
Calculate

a) refrigerator efficiency

b) heat engine efficiency and ##|W_{eng}|## output by the engine if the refrigerator uses 1570J to run

Note that there are other further items in the original problem but my question is about the calculation of engine work in part b).
The efficiency of a heat pump is

$$\mathcal{\epsilon}_{ref}=\frac{T_C}{T_H-T_C}=\frac{275}{29}=9.48$$

where ##T_H=304K## is the hot reservoir and ##T_C=275K## is the cold reservoir.

The efficiency of the heat engine is

$$\mathcal{\epsilon}_{eng}=1-\frac{T_C}{T_H}=1-\frac{75}{304}=0.753$$

where now we have a hot reservoir at 304K (the exhaust from the refrigerator) and a cold reservoir at 75K (the liquid nitrogen).

Schematically, here is the reverse Carnot cycle that represents the heat pump (ie, the refrigerator):

1719978892673.png


Note that I am naming the individual processes as -A, -B, -C, and -D because the corresponding heat engine has processes A, B, C, and D.

The refrigerator uses 1570J to run. This is the work required in order to obtain a certain amount of heat from the refrigerator's cold reservoir.

Let's denote this certain amount of heat as ##|Q_{-C}|##. This is the absolute value of the heat flow in process -C in the picture above.

Then

$$\mathcal{\epsilon}_{ref}=9.48=\frac{|Q_{-C}|}{1570\text{J}}$$

$$\implies |Q_{-C}|=9.48\cdot 1570=14.8\text{kJ}$$

As far as I understand, this is not the heat exhausted by the refrigerator. This is the heat removed from the cold reservoir.

The heat exhausted is the heat in process -A, namely, the heat that is transferred to the hot reservoir.

1570J represents the total work in the cyclic process.

$$|W_{pump}|=1570\text{J}=|W_{-C}+W_{-A}|=|-(Q_{-C}+Q_{-A})|$$

We can calculate ##W_{-C}## and ##W_{-A}## and show that ##W_{-C}+W_{-A}=-(Q_{-C}+Q_{-A})>0##. Thus, we can remove the absolute values and so

$$Q_{-A}=-Q_{-C}-W_{pump}$$

$$=-9.48\cdot 1570 - 1570=-10.48\cdot 1570$$

$$=16.45\text{kJ}$$

This is the heat exhausted by the refrigerator.

The work done by the engine is then

$$|W_{eng}|=0.753\cdot 16.45\text{kJ}=12.39 kJ$$

This problem is from EdX and has automated grading. The answer for this last calculation is, according to EdX, 11.2 kJ.

I am wondering where the discrepancy comes from.

More importantly, I am wondering if the reasoning I used above is correct?
 
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  • #2
If you had an unlimited supply of liquid ##N_2## and a Carnot engine you could dispense with the refrigerator and just run the Carnot engine between the hot reservoir (ambient temperature 304K) and the liquid ##N_2##. So long as the Sun maintained the temperature of the hot reservoir it would keep going as long as you maintained your supply of liquid ##N_2##.

Also, I would question the correctness of the assumption that the refrigerator can keep pumping 1570 J per cycle indefinitely without lowering the temperature of the cold reservoir and, therefore, the COP of the refrigerator.

AM
 

FAQ: Work done by heat engine that uses exhaust from heat pump

What is a heat engine?

A heat engine is a device that converts thermal energy into mechanical work by utilizing a temperature difference between two heat reservoirs. It operates on a cyclic process, absorbing heat from a high-temperature source, performing work, and releasing some waste heat to a low-temperature sink.

How does a heat engine use exhaust from a heat pump?

A heat engine can utilize the exhaust heat from a heat pump as its heat source. The heat pump transfers heat from a low-temperature reservoir to a high-temperature reservoir, and the waste heat released during this process can be harnessed by the heat engine to perform work, increasing overall energy efficiency.

What is the efficiency of a heat engine using exhaust from a heat pump?

The efficiency of a heat engine depends on the temperatures of the heat reservoirs it operates between. When using exhaust from a heat pump, the efficiency can be calculated using the Carnot efficiency formula, which is based on the absolute temperatures of the high and low-temperature reservoirs. However, real-world efficiencies will be lower due to irreversibilities and non-ideal conditions.

Can a heat engine improve the overall energy efficiency of a system that includes a heat pump?

Yes, integrating a heat engine with a heat pump can improve the overall energy efficiency of the system. By utilizing the waste heat from the heat pump, the heat engine can convert some of that thermal energy into mechanical work, thereby reducing the net energy consumption of the system and maximizing the use of available energy resources.

What are some practical applications of heat engines using heat pump exhaust?

Practical applications include combined heat and power (CHP) systems, where both heating and electricity generation are achieved from the same energy source. Additionally, in industrial processes where heat pumps are used for heating, the exhaust can be redirected to drive a heat engine, increasing the overall energy recovery and efficiency of the system.

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