- #1
JUSTaROCK
- 8
- 0
Homework Statement
A fully loaded freight elevator has a cab with a total mass of 1490 kg, which is required to travel upward 58
m in 2.1 minutes, starting and ending at rest. The elevator's counterweight has a mass of only 985 kg, so the
elevator motor must help. What average power is required of the force the motor exerts on the cab via the cable?
Homework Equations
F=ma
W=F * D D= displacement (distance traveled)
P = W/t P= power, t = time
v=u + at u = initial velocity, v = final velocity
v^2 = u^2 +2aD
D= ut + 1/2(a)t^2
The Attempt at a Solution
I have tried to solve for a by using the formula D= ut + 1/2(a)t^2 then taking that a and multiplying it with the mass then multiplying that by distance and then dividing by the time needed to be done but i can't get it right and i feel like i should do something with the counterweight but i don't know what any thing will help thank you