Work done by Tension Ques: Friction 0.5n

[naman0804]

ques: how fast block moves after sliding 100 cm on incline?[by energy conservation]
A frictional force of 0.5 n actsdoubt: should work done by tension be accounted?

 

[Spinnor]

Did you give us all the information that you were given?

 

[naman0804]

yes i did ... i just want to know if tension does work

 

[Spinnor]

Before the block moves you can set the total energy to zero, after the block has moved 1m the total energy is still zero and is,

0 = .5N X 1m + mV^2/2 - mgh = force times distance + kinetic energy - potential energy

where h is the vertical distance the block falls.

 

[rwisz]

Yes, work done by tension should be accounted for in this scenario. When the block is sliding on the incline, there are two forces acting on it - the frictional force and the tension force. The tension force is responsible for pulling the block up the incline, while the frictional force is acting in the opposite direction, slowing down the block's motion.

In order to determine the speed of the block after sliding 100 cm on the incline, we can use the principle of energy conservation. This principle states that the total energy of a system remains constant, meaning that the initial energy of the block is equal to the final energy after sliding 100 cm.

In this case, the initial energy of the block is equal to its potential energy at the top of the incline, given by mgh, where m is the mass of the block, g is the acceleration due to gravity, and h is the height of the incline. The final energy of the block is equal to its kinetic energy, given by 1/2mv^2, where v is the final velocity of the block.

Using the principle of energy conservation, we can equate the initial energy to the final energy and solve for v:

mgh = 1/2mv^2

Solving for v, we get:

v = √(2gh)

Now, to account for the work done by tension, we can use the equation W = Fd, where W is the work done, F is the tension force, and d is the distance over which the force acts. In this case, the work done by tension is equal to the tension force multiplied by the distance the block has slid, which is 100 cm or 1 meter.

Therefore, the final equation for the speed of the block after sliding 100 cm on the incline is:

v = √(2gh + W/F)

Substituting the values of g, h, W, and F, we can calculate the final velocity of the block. So, yes, the work done by tension should be accounted for in determining the speed of the block after sliding 100 cm on the incline.