Work done by the gas during the -

In summary, the problem involves a cyclic process ABCA performed on a sample of 2.0 moles of an ideal gas. A total of 1200J of heat is withdrawn from the sample during the process and the task is to find the work done by the gas during the part BC. The given graph is a T-V graph and the work done during CA is 0 as the volume is constant. The work done during the process AB minus the work done during the process CB is equal to the loss of heat. The internal energy change is also 0 since the process is cyclic. The process AB is a straight line from the origin, indicating constant pressure. The coordinates of points A, B, and C are not provided,
  • #1
satishinamdar
22
0
Work done by the gas during the ---

Sir,
My son has tried to solve this problem,He is not able to get the answer.Can you please help me to help my son in solving the problem?


Consider the cyclic process ABCA, shown in the fig.performed on a sample of 2.0 mole of an ideal gas.A total of 1200J of heat is withdrawn from the sample in the process.Find the work done by the gas during the part BC.

i c.
i .b
i .
i .
i .
i......
o
unable to draw graph. Think of a straight line from pt.c downward on line ob it meets the line at pt.a
there is a curved line bc.sinking downward.

can you pl help?(also let me know how to drw diagrams or graphs )
Regards
 
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  • #2
Welcome to PF satishinamdar, We have a section of the forums dedicated to homework and coursework questions. Could you show us what you/your son has attempted thus far? Any working / thoughts? Is the graph a pressure volume curve? If so, the work done is the area encolsed by the curve.

~H
 
  • #3
Work done by gas

Sir,
I am greatful to receive your reply.
The attempt made was as follows
the given graph is a t-v graph
the work done during CA is 0 as the volume is constant
therefore work done during the process AB minus work done during the process CB =loss of heat
as the process is cyclic the change in the internal energy is 0
AB is straight line from origin hence press is const
calculating pressure and volume at A as follows
0.00224m^3 occupy 1 mol of gas at stp and then relating it at 2 mol and 300k and 500k...
work done at AB is w=p(v2-v1).
but the answers are not matching ans given in the textbook is (-4520joules)
kindly let me know if i am in the right direction
Warm Regards
-tejas inamdar
 
  • #4
Work done graph

I have attached the graph now.
tejas inamdar
 
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  • #5
Dear Sir,
Kindly help in solving this .
Regards
 
  • #6
Your graph isn't attached. I can't see it.
 
  • #7
Work done by gas

jpg .word file attached.
 

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  • #8
Is this a P-V diagram or a T-V diagram? Since there are no units how do we determine the coordinates of A B and C? If you want us to help, you have to give us all the information. Please write out the complete question. This will include details about the kind of transition between C and B (eg. adiabatic, isobaric), the temperatures at C and one of A or B and the volumes at A and B.

AM
 
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FAQ: Work done by the gas during the -

What is "work done by the gas"?

The work done by the gas refers to the amount of energy transferred by the gas as it performs work on its surroundings.

How is work done by the gas calculated?

The work done by the gas is calculated by multiplying the force exerted by the gas by the distance over which the force is applied.

What are the units of work done by the gas?

The units of work done by the gas are Joules (J) in the SI system and foot-pounds (ft-lb) in the imperial system.

How does work done by the gas affect the internal energy of the system?

The work done by the gas can either increase or decrease the internal energy of the system, depending on the direction of the work (positive or negative) and the type of process (isobaric, isothermal, adiabatic, etc.).

Can the work done by the gas be negative?

Yes, the work done by the gas can be negative if the gas is expanding against an external force, as the gas is doing work on its surroundings and losing energy in the process.

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