- #1
lynchdemartin
- 9
- 0
A 50.0 kg crate is dragged at a constant velocity of 1.5 m/s for a distance of 8.0 m. If the force of friction on the crate is 225 N, how much work was done by the person to drag the crate over the 8.0 m distance if the rope used to drag the crate was directed at 20degrees angle above the horizontal?
my work:
mass 50kg
distance 8m
angle 20 degrees
Force of Friction 225N
since we have a constant velocity Fnet = 0
Fnet = T - Ff
Solve for T
0 = T - 225N
T = 225N
therefore T x distance moved by the rope x cosx = work done
so I got 225N x 8m x cos20 = 1690 J
However the answer sheet says it's 1800 J...
my work:
mass 50kg
distance 8m
angle 20 degrees
Force of Friction 225N
since we have a constant velocity Fnet = 0
Fnet = T - Ff
Solve for T
0 = T - 225N
T = 225N
therefore T x distance moved by the rope x cosx = work done
so I got 225N x 8m x cos20 = 1690 J
However the answer sheet says it's 1800 J...