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VitaX
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Homework Statement
A worker pushed a 16 kg block 6.7 m along a level floor at constant speed with a force directed 32° below the horizontal. If the coefficient of kinetic friction between block and floor was 0.34, what were (a) the work done by the worker's force and (b) the increase in thermal energy of the block-floor system?
Homework Equations
W = (K2 - K1) + (Ug2 - Ug1) + fkd
The Attempt at a Solution
Part a:
W = 0 + 0 + fkd
W = Friction coefficent*n*d
In this case n=mg
W = .34*(16*9.8)*6.7 = 357.1904 J
Part b:
I'm thinking its either 0 or 357.1904 J, but I'm not sure that's why I posted this. I mean I just found the change in thermal energy in part a pretty much. So is that my answer to part b then since it is asking for the increase in thermal energy of the block-floor system? Or is there more to it?