- #1
c77793
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I've always seen Work as an extra mechanic energy given to the system... but i really can't figure it out :
If we lift a 2kg ball, that's steady, using g as 10m/s², with 25N, we'll have a 5N up resultant force...
after its 5meters up, the resultant work will be 25J (5N.5m), but the potential energy by itself will be 100J (20kgx10m/s²x5m) and the kinetic energy will be 25J (i found it using the F=ma to discover de aceleration and then using torricelli's formula..)..
How can I give 25J to a system and it become 125J?
If the same ball were dragged along the floor, with 25N, and a friction force of 20N , after 5 meters, the resultant work would be 25J, the same as the extra mechanic energy ... can someone help me?
If we lift a 2kg ball, that's steady, using g as 10m/s², with 25N, we'll have a 5N up resultant force...
after its 5meters up, the resultant work will be 25J (5N.5m), but the potential energy by itself will be 100J (20kgx10m/s²x5m) and the kinetic energy will be 25J (i found it using the F=ma to discover de aceleration and then using torricelli's formula..)..
How can I give 25J to a system and it become 125J?
If the same ball were dragged along the floor, with 25N, and a friction force of 20N , after 5 meters, the resultant work would be 25J, the same as the extra mechanic energy ... can someone help me?