WORK/LEVERAGE comparison HELP

[xengineguy]

I need to compare two ICE engines. I need to know the "work" of one compared to another.
Let's say the first engine has a bore of 3'' and a sroke of 3" connecting rod 5.25. If you need
cylinder presure,say PCP is 5000psi At 20 degrees ATDC and tapers to 800psi at 90 degrees ATDC. The second engine has the same bore and stroke,and same pressures. The only difference is the effective leverage, which is 10"-1.5" at TDC and 10"+1.5" at BDC,and no connecting rod angle (if that matters)?
I'am not interested in horse power, I just need to compare the work each could do with equal cylinder pressures/force? The second engine is not a conventional crank engine.
I hope this can be solved with the info provided if not please tell me.
Thanks Mike

 

[berkeman]

Thread moved to ME/Aero for better views. xengineguy, even though this if for a project (so it qualifies for the general forums as opposed to the Homework Help forums), we still would prefer that you show us your work and thoughts so far, in order for us to help you figure this out.

 

[russ_watters]

Do you know the definitions of power and work?

 

[xengineguy]

Do you know the definitions of power and work?

Ok fill me in, I was looking for a simple way to compare.

 

[xengineguy]

Thread moved to ME/Aero for better views. xengineguy, even though this if for a project (so it qualifies for the general forums as opposed to the Homework Help forums), we still would prefer that you show us your work and thoughts so far, in order for us to help you figure this out.

Thanks for the move,berkeman.
The engine as designed,is a twin cylinder two stroke. The cylinders are attached to the output shaft,and 90 degrees compared to the shaft axis. Cylinder spacing is 180 degrees from each other. As the pistons move out from the axis the rollers on the pistons contact
the inner surface of the (stator).The inner surface of the stator has a pair of lobes,spaced180 degrees apart. These lobes act similer to a crankshaft in a conventional engine. The first ramp of the lobe is the compression stroke,the second ramp is the power stroke. NOTE: The pistons move down, away from the axis for the power stroke..The lobe height is equal to the stroke of the engine.
The max leverage is not limited to half the stroke...as per conventional engines. I think it is much more? If you would like to see a video of the prototype running go to YOUTUBE /marckel rotor stator engine.