Work out the tension in the rope

[Gughanath]

Im revising for an exam and I am practising past paper questions. I came across this question I am stuck. Please help.
A sledge of mass 78kg is pulled up a slope by a rope. The slope is rough and is inclined at an angle of 22.6 degrees to the horizontal. The coefficent of friction between the sledge and the slope is 0.25. The sledge is accelerating up the slope at 0.5ms^-2.

!I am asked to work out the tension in the rope!
I built an equation using all the forces that act on the particle, that is:
F-T-Fr-78gsin22.6=39N
F= force applied by rope
T= Tension
Fr= Friction

I worked out the friction to be 176.4N. I can't continue now, please help.

 

[Nylex]

You don't need the F there, it's the same as the tension (and so the T should be +ve).

 

[Gughanath]

Can you explain this. Why is the tension same as the force?

 

[Nylex]

The rope is pulling the sledge, the pulling force is making the rope taut!