Work Power Engergy Thrown Toilet Roll Problem

In summary, the conversation is about a Lions fan throwing a roll of toilet paper at a game. The question is how fast the roll is going when it hits an opposition player 17.0 m below. The person asking for help attempted to use the equation 1/2mv^2 = mgh, but got confused and asked for assistance. The person responding suggests using the equation Initial KE + initial PE = final KE and asks for clarification on the direction of the throw.
  • #1
jojo711
27
0

Homework Statement


A pure silver Lions fan throws a roll of toilet paper at 11.0 m/s from her seat at Ford's Field during a recent game. How fast is the 0.4 kg roll going when it strikes an opposition player 17.0 m below?

Homework Equations


1/2mv^2 = mgh <-- i think.

The Attempt at a Solution


I did 1/2mv^2 = mgh and got something like 18.25 and then got totally confused and did not know how to do it. Please help. I am totally lost. thanks please answer in the next 20 mintues and you will receive lots of love. Thanks.
 
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  • #2
Yes, definitely an energy question! But I think you have oversimplified a bit. Wouldn't it be
Initial KE + initial PE = final KE
 
  • #3
I did:
mgh+1/2mv^2
and got an answer and I don't know what to do from there.
 
  • #4
Initial KE + initial PE = final KE
mgh+1/2mv^2 = 1/2mV^2
Fill in the numbers.
 
  • #5
Which direction are they throwing the roll in?
 
  • #6
We can find the magnitude of the velocity from the final KE. But not the direction because the initial direction isn't given.
 

FAQ: Work Power Engergy Thrown Toilet Roll Problem

What is work, power, and energy?

Work, power, and energy are all related concepts that describe the physical movement or change of an object. Work is the force applied to an object multiplied by the distance it is moved. Power is the rate at which work is done, or the amount of work done per unit of time. Energy is the ability to do work, and it can come in various forms such as kinetic, potential, thermal, etc.

How do you calculate work, power, and energy in the "Thrown Toilet Roll" problem?

In the "Thrown Toilet Roll" problem, work can be calculated by multiplying the force applied (throwing the roll) by the distance it travels. Power can be calculated by dividing the work done by the time it takes to throw the roll. Energy can also be calculated by multiplying the force by the distance, or by using the formula for kinetic energy (1/2 * mass * velocity^2).

What is the relationship between work, power, and energy in this problem?

In this problem, work is the force applied to throw the toilet roll, power is the rate at which the work is done, and energy is the ability to do the work. They are all interrelated and depend on each other to solve the problem.

How does the weight of the toilet roll impact the results of the problem?

The weight of the toilet roll will impact the results of the problem because it affects the force applied to throw the roll. A heavier roll will require more force to throw, resulting in more work and power. However, the weight will not affect the energy of the roll, as it is dependent on the velocity and not the mass.

What are some real-life applications of this problem?

This problem can be applied in real-life scenarios, such as calculating the work and power required to throw a ball, or the energy needed to launch a rocket. It can also be used in sports to analyze the performance of athletes, such as measuring the power of a basketball player's shot or the energy exerted by a runner during a race.

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