- #1
eggman100
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Homework Statement
Using mass = 2.473x10^23kg and Density = 7.481g/cm^3 work out the radius of said sphere,
Homework Equations
D=M/V
4/3∏r^3
The Attempt at a Solution
D=M/V
DV=M
V=M/D
Mass = 2.473x10^23kg
V=2.473x10^23kg / 7.481g/cm^3
V=2.473x10^23kg / 0.007481kg/cm^3
V= 3.31x10^24 cm
V= 3.31x10^22 km
Vol of sphere = 4/3∏r^3
3√(3.31x10^22/(4/3∏)) = 19918033Km
I assume I have a massive problem in my calculations (I think there's a problem where i changed the 7.481g/cm^3 into 0.007481kg/cm^3) but I'm still pretty unsure about that one, since my answer at the end is in kilograms and the units i used when changing the decimal is in cm^3, I think that's my problem but I'm not sure)
Thanks
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Tried to change it into kg/km^3 and i got 2.473x10^23kg / 748.1
then cube-root((3.31x10^20)/(4/3Pi) to get 4291210 km, still unsure =/
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Changed it :
(2.473x10^23kg) / (7.481g/cm^3) into
(2.473 x 10^23kg) / (0.007481kg/cm^3) noting that it is CM(i remembered at the end ;) )
3.666622109x10^25cm <--- 4/3PiR^3
divide
3.666622109x10^25cm by 4/3Pi then
cuberoot to get:
206091073.4 CM(!) / 100 to get meters (=)
2060910.734 M / 1000 to get KM (=)
2060.910734 KM -
rounded to 2061km (4.S.F)
I hope that's right, it seems reasonably accurate,
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