- #1
reefcake
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Hi I'm forensics student and I'm having trouble with this problem as i don't know how to solve it I would really like to to know the method.
Calculate the speed in ms-1 at which a parked 1840kg "car A" will be traveling once "car B" crashes into it. assuming that "car B" continues to move forward at 8.4ms-1 after the crash.
info on Car A: Mass(m)= 1840kg, Speed(v)=0 ms-1
info on Car B: Mass(m)= 1400kg, Speed(v)= 26.82 ms-1 Momentum(p), 37548 kg-ms-1
ending speed= 8.4ms-1, Ending momentum= 11760 kg-ms-1
p=mv (conservation momentum)
F=ma (Newtons 2nd law of motion)
A= uv/t (working out acceleration)
Thanks
reefcake
Homework Statement
Calculate the speed in ms-1 at which a parked 1840kg "car A" will be traveling once "car B" crashes into it. assuming that "car B" continues to move forward at 8.4ms-1 after the crash.
info on Car A: Mass(m)= 1840kg, Speed(v)=0 ms-1
info on Car B: Mass(m)= 1400kg, Speed(v)= 26.82 ms-1 Momentum(p), 37548 kg-ms-1
ending speed= 8.4ms-1, Ending momentum= 11760 kg-ms-1
Homework Equations
p=mv (conservation momentum)
F=ma (Newtons 2nd law of motion)
A= uv/t (working out acceleration)
Thanks
reefcake