Write 2^2 * 3 * 5 as a natural number?

[penza]

1) Write 2^2 * 3 * 5 as a natural number? I get 60 is it right or should i put 4*3*5= 60
2) Write 420 as the product of its prime factors in exponent form?
What do i have to do ?

 

[arildno]

1) Yes; it doesn't matter.
2) Rewrite 420 in the shape that 60 was presented as in a)

 

[tacman]

1) Yes, 60 is the correct answer. 2^2 * 3 * 5 is already in its simplest form, so there is no need to further simplify it.
2) To write 420 as the product of its prime factors in exponent form, you would need to find the prime factors of 420, which are 2, 2, 3, 5, and 7. Then, you would write it as 2^2 * 3 * 5 * 7. This shows that 420 is the product of 2 multiplied by itself twice, 3, 5, and 7.