X^0 - 3Find Older Derivatives of y

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The discussion revolves around finding the derivatives of the function y = (1/2)x^4 - (3/2)x^2 - x. Participants clarify that the notation for derivatives is inconsistent, with y4 being incorrectly used instead of y'. The correct differentiation of the terms reveals errors in the original calculations, particularly in the handling of the derivative of -(3/2)x^2. The conversation highlights the importance of proper notation and accurate differentiation in calculus. Overall, the focus remains on correcting the derivative calculations for the given function.
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Q Find all older derivatives



y = X^4/2 = 3/2X^2 -X



y4 = 2X^2 - 3 x ^ 1 - 0

y4 = 4X^1 - 3 -0

y4 = 7
 
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thats not so much a question as it is random keystrokes... ;)
 
r-soy said:
Q Find all older derivatives



y = X^4/2 = 3/2X^2 -X
Do you mean y = (1/2)x4 - (3/2)x2 - x?
r-soy said:
y4 = 2X^2 - 3 x ^ 1 - 0
What is y4 supposed to be? Since you have taken the derivative, this should be y'. Of the three terms you differentiated on the right side, only one is correct: d/dx[-(3/2)x2] = -3x. The other two terms have errors.
r-soy said:
y4 = 4X^1 - 3 -0
?
r-soy said:
y4 = 7
?
 

Thread 'Distance between a Clock's hands when the distance is increasing most rapidly'

Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?
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