X and Y coordinates of an oscillating object on a spring.

  • #1
phantomvommand
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Homework Statement
Consider a mass m on a table attached to a spring at the origin with zero relaxed
length, which exerts the force
F = −kr
on the mass. We will find the general solution for r(t) = (x(t), y(t)) in two different ways.
(a) Directly write down the answer, using the fact that the x and y coordinates are independent.
(b) Sketch a representative sample of solutions. What kind of curve does the trajectory follow?
Relevant Equations
##m\ddot x = kx## solution is ##x(t) = A\cos(\omega t + \phi)##
##r^2 = x^2 + y^2##
I get that:
##x(t) = A\cos(\omega t + \phi)##
##y(t) = A\sin(\omega t + \phi)## (from the above relevant equations). This agrees with the solution for part (a).

However, the solution manual claims in part (b) that:
In the case where ϕ1 = ϕ2 = 0 and A = B, the mass moves in a circle centered at the origin.More generally, when the angles ϕi are unequal, the mass can move in an ellipse with centerat the origin.

Is there any way to prove this, or explain this physically? I am especially dubious of the claim that when ϕ1 = ϕ2 = 0 and A = B, it is a circle, because this situation, physically, at time t = 0, should represent a simple 1D motion along the x-axis, since the spring was never stretched in the y-direction to begin with!
 
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  • #2
phantomvommand said:
##x(t) = A\cos(\omega t + \phi)##
##y(t) = A\sin(\omega t + \phi)## (from the above relevant equations).
except that, as indicated later, the amplitude and phase constants can be different. Only the frequency must be the same.
phantomvommand said:
However, the solution manual claims in part (b) that:
In the case where ϕ1 = ϕ2 = 0 and A = B, the mass moves in a circle centered at the origin.
Easily proved. Write down the expression for ##x^2+y^2##.
Slight variation for the ellipse case.
phantomvommand said:
since the spring was never stretched in the y-direction to begin with!
You don’t know that, but it’s not just a question of initial displacement. In the general case, it may have been given some initial velocity.
 
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  • #3
phantomvommand said:
Is there any way to prove this, or explain this physically?
In first instance this is math. You have two seond order differential equations, so four initial conditions.
For example ##x, \dot x, y, \dot y## at ##t=0##.
Or ##A, \phi_1, B, \phi_2## at ##t=0##.
Setting
phantomvommand said:
ϕ1 = ϕ2 = 0 and A = B
leaves only one degree of freedom. And sure enough the "choice"
##x = A \cos(\omega _t),\ \ y=\sin(\omega t)## describes circular motion,
with very specific initial conditions ##x=A, \dot x=0, y=0, \dot y=\omega A## at ##t=0##

Ah, hello @haruspex !

##\ ##
 
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  • #4
phantomvommand said:
physically, at time t = 0, should represent a simple 1D motion along the x-axis, since the spring was never stretched in the y-direction to begin with!
So: no! Spring not stretched in the ##y## direction at ##t=0## doesn't mean never stretched. ##\dot y \ne 0## at t=0 means it does gets stretched in the ##y## direction.

##\ ##
 
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FAQ: X and Y coordinates of an oscillating object on a spring.

What are X and Y coordinates in the context of an oscillating object on a spring?

The X and Y coordinates represent the position of the oscillating object in a two-dimensional space. In the case of a spring, the X coordinate typically represents the horizontal displacement from the equilibrium position, while the Y coordinate can represent the vertical position, which may change depending on the spring's orientation and the object's motion.

How do you calculate the X and Y coordinates of an oscillating object on a spring?

The X coordinate can be calculated using the formula X(t) = A * cos(ωt + φ), where A is the amplitude, ω is the angular frequency, t is time, and φ is the phase constant. The Y coordinate can be determined based on the vertical position of the spring or the gravitational effect on the object, which may involve additional parameters like the spring constant and mass.

What factors affect the oscillation of an object on a spring?

Several factors influence the oscillation of an object on a spring, including the mass of the object, the spring constant (stiffness), the amplitude of oscillation, and any damping forces such as friction or air resistance. These factors determine the frequency and amplitude of the oscillation, which in turn affect the X and Y coordinates over time.

How does damping affect the X and Y coordinates of an oscillating object?

Damping refers to the reduction in amplitude of oscillation over time due to energy loss, often from friction or air resistance. As damping increases, the X and Y coordinates will show a decrease in amplitude, leading to a more rapid convergence towards the equilibrium position. The motion will become less periodic and more irregular as damping increases.

Can the motion of an oscillating object on a spring be represented graphically?

Yes, the motion of an oscillating object on a spring can be represented graphically using a parametric plot, where the X coordinate is plotted against the Y coordinate over time. This creates a visual representation of the object's trajectory, showing how it moves through space as it oscillates, typically resulting in a sinusoidal wave pattern if viewed over a complete cycle.

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