Young's Modulus: maximum depth of mine

In summary, the conversation discusses the difficulties of drilling deep into the Earth and poses a question about the maximum length of a steel cable that can be lowered into a deep mine without exceeding the breaking stress of the material. The solution involves considering the cable's weight, weight density, length, and area to ensure that the maximum stress does not exceed the given value.
  • #1
mmylo
1
0

Homework Statement



Although human beings have been able to fly hundreds of thousands of miles into outer space, getting inside the Earth has proven much more difficult. The deepest mines ever drilled are only about 10 miles deep. To illustrate the difficulties associated with such drilling, consider the following: The density of steel is about 7900 kilograms per cubic meter, and its breaking stress, defined as the maximum stress the material can bear without deteriorating, is about 2.0x10^9 pascals. What is the maximum length of a steel cable that can be lowered into a mine? Assume that the magnitude of the acceleration due to gravity remains constant at 9.8 meters per second per second.

Homework Equations



Stress=F / A
Y=( F / A ) / ( delta L / L )

The Attempt at a Solution



I really don't know where to begin.
 
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  • #2
mmylo said:

Homework Statement



Although human beings have been able to fly hundreds of thousands of miles into outer space, getting inside the Earth has proven much more difficult. The deepest mines ever drilled are only about 10 miles deep. To illustrate the difficulties associated with such drilling, consider the following: The density of steel is about 7900 kilograms per cubic meter, and its breaking stress, defined as the maximum stress the material can bear without deteriorating, is about 2.0x10^9 pascals. What is the maximum length of a steel cable that can be lowered into a mine? Assume that the magnitude of the acceleration due to gravity remains constant at 9.8 meters per second per second.

Homework Equations



Stress=F / A
Y=( F / A ) / ( delta L / L )

The Attempt at a Solution



I really don't know where to begin.
mmylo, welcome to PF!
You don't need to know Young's modulus or deformations to solve this problem. It is asking you to find the maximum length of the cable such that the maximum stress, due to the cables weight, does not exceed the given value of the maximum stress allowed. The cable's weight is a function of its weight density, length, and area. It's stress is just F/A. Does this give you a clue to solve the problem?
 
  • #3


Young's Modulus is a measure of a material's stiffness or elasticity and is often used to determine the amount of stress a material can withstand before breaking. In this case, we can use Young's Modulus to calculate the maximum length of a steel cable that can be lowered into a mine.

To begin, we need to use the formula Y=( F / A ) / ( delta L / L ) , where Y is Young's Modulus, F is the force being applied, A is the cross-sectional area of the cable, delta L is the change in length, and L is the original length of the cable.

In this scenario, the force being applied is the weight of the cable, which can be calculated using the density of steel and the maximum depth of the mine. The cross-sectional area of the cable can be calculated using the diameter of the cable.

Once we have these values, we can plug them into the formula and solve for the maximum length of the cable. This will give us an estimate of the maximum depth that the cable can be lowered into the mine without breaking.

However, it's important to note that this calculation does not take into account other factors such as the strength of the cable itself and the conditions inside the mine. Therefore, it is important for engineers and scientists to consider all of these factors when determining the maximum depth of a mine.
 

FAQ: Young's Modulus: maximum depth of mine

What is Young's Modulus and how is it related to the maximum depth of a mine?

Young's Modulus is a material property that measures the stiffness of a material. It is defined as the ratio of stress (force per unit area) to strain (change in length per unit length) in a material. In the context of mining, Young's Modulus is used to determine the maximum depth that can be safely excavated without the risk of collapse.

How is Young's Modulus calculated?

Young's Modulus is calculated by dividing the stress by the strain. This can be represented with the formula E = σ/ε, where E is Young's Modulus, σ is stress, and ε is strain. The units for Young's Modulus are typically in Pascals (Pa) or Gigapascals (GPa).

What factors affect the value of Young's Modulus?

The value of Young's Modulus can vary depending on several factors, including the type of material, temperature, and the direction of the force applied. For example, metals tend to have higher Young's Modulus values compared to polymers and ceramics.

How is Young's Modulus used in mining operations?

In mining, Young's Modulus is used to determine the maximum depth that can be excavated without causing the mine walls to collapse. This is done by measuring the strength of the rock or soil surrounding the mine and calculating the maximum stress that it can withstand without deforming. The value of Young's Modulus is also used to design support systems, such as pillars and walls, to prevent collapse.

Can Young's Modulus change over time in a mine?

Yes, Young's Modulus can change over time in a mine due to factors such as stress and strain from mining activities, changes in temperature and moisture levels, and geological processes. It is important for mining companies to regularly monitor and assess the condition of the mine walls to ensure the safety of workers and the stability of the mine.

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