- #1
DracoMalfoy
- 88
- 4
Homework Statement
Superman pulls on a steel post to trap a supervillian. The post has a cross-sectional area of 30cm^2 and a length of 2m. If Superman applies a force of 6X10^6N by how much is the length of the post increased?
A) 2mm
B) 7mm
C) 1.2cm
D) 1.7cm
E) 2cm
Homework Equations
F/A= Y(of steel post) ⋅ΔL/Li
F= 6x10^6N
A=30cm^2= .3m^2
Li=2m[/B]
The Attempt at a Solution
[/B]
I know I'm supposed to find the change in length, but when I use this equation, I'm getting 1.9 which isn't an answer choice. I'm not sure what I'm doing wrong here.