- #1
mikefitz
- 155
- 0
A wire of length 4.95 m with a cross-sectional area of 0.103 cm^2 stretches by 6.55 mm when a load of 0.94 kN is hung from it. What is the Young's modulus for this wire?
FA = Y (delta L/L)
0.103 (cm^2) = 1.03 × 10-5 m^2
6.55 millimeters = 0.00655 meters
= 9221.4 N x 1.03 × 10-5 m^2 = .09498
0.00655m / 4.95m = 0.00132323232
.09498 / 0.00132323232 = 71.7787788 Pa ?
what did i do wrong?
FA = Y (delta L/L)
0.103 (cm^2) = 1.03 × 10-5 m^2
6.55 millimeters = 0.00655 meters
= 9221.4 N x 1.03 × 10-5 m^2 = .09498
0.00655m / 4.95m = 0.00132323232
.09498 / 0.00132323232 = 71.7787788 Pa ?
what did i do wrong?