- #1
Ronaldo95163
- 77
- 1
So we started looking at Zener Diodes in our electronics course.
What I am having trouble with is the interpretation of the graph.
For the example our diode has a Zener Voltage is 6.2V. I understand what happens in the positive half but when the direction changes is where I get confused.
Why is the pd across the diode 0.7V after clipping? If the polarities switch on the negative cycle of the input signal why would it be -0.7V and not 0.7V?
What I am having trouble with is the interpretation of the graph.
For the example our diode has a Zener Voltage is 6.2V. I understand what happens in the positive half but when the direction changes is where I get confused.
Why is the pd across the diode 0.7V after clipping? If the polarities switch on the negative cycle of the input signal why would it be -0.7V and not 0.7V?