What is the Constant Torque Applied in a Simple Piston Engine?

In summary: That's a little ambiguous. I think what you mean is that you realized to calculate the total KE of the rod at any point, you would need to add the rotational KE to the horizontal KE.But you also said, "If i was to use the center of mass I would need its horizontal KE, vertical KE and rotational KE." That's not true. You need the translational KE of the CM (which is the same as the translational KE of any other point on the rod if the rod is rotating about its CM), and you need the rotational KE about the CM. You do not need the vertical KE of the CM, which is zero.And finally, yes, if you choose the reference point to
  • #1
Jrak11
4
0

Homework Statement


Find the constant Torque being applied.
We are given a diagram of a piston engine, along with the masses of piston, flywheel and rod connecting the two. I know that the expanding gas in the piston does 4 kJ of work. I know that at the beginning of each rotation the engine is at 350 rpm. I know that a constant torque is being applied on the fly wheel.

Homework Equations


work=Torque*Angular displacement


The Attempt at a Solution


4kJ = T*2pi
T=4000/2Pi

I feel this is wrong however because I have not taken into account that the piston has been moved back and forth, and we knew it's mass. I can easily calculate the force on the piston at any point in the rotation so I would have thought there is some work done by its movement. Or does this do no net work since the net displacement is zero??
Thanks a heap for any help
 
Physics news on Phys.org
  • #2
Welcome to Physics Forums.

It is difficult to understand without seeing the actual figure. If you could attach a copy of it, that would be helpful. To attach a figure, click the "Go Advanced" button below, then click the paper clip icon just to the right of the smiley-face icon.
 
  • #3
Ok Here is an image:
Elevation-of-simple-reciprocating-steam-engine.jpg


I also have a question about when I am calculating the rotaitonal KE of the rod. Does it rotate around an axis through its centre, or the axis where it connects to the piston?
 
  • #4
Well, I'm still perplexed by this one. Have you posted all the given information? Copying the problem statement exactly, word-for-word, is generally a good idea.

To answer two of your questions: the work done by the piston in one cycle is not zero if there is any net heat either added or taken away during a cycle. As for the KE of the rod, you can calculate the total KE as rotational KE about the center-of-mass, plus the translational KE of the center-of-mass. Since the end point is not actually fixed in place, I would not use it as a reference point for the rotation.

Meanwhile, I have asked some of our designated "Homework Helpers" if they have any ideas.
 
  • #5
I guess I should have been more specific. I meant, is there any work done in moving the mass of the piston back and forth. Not turning the wheel or accelerating the engine, just moving the piston.

And as to the other part, Is there a reason why it would be better to use the CM of the rod as the zero point? It too is moving, so why is it not better to choose the lesser of two evils and use the rotation around the piston joint instead.
 
  • #6
I think that your initial calculation is correct. Think about it this way: each cycle, the piston supplies 4kJ of new energy, yet the flywheel's speed never increases. This means that the constant torque must be draining 4 kJ every cycle. If it drained any more or less, the flywheel would be rotating faster or slower than 350 rpm at the start of the next cycle.

Jrak11 said:
I guess I should have been more specific. I meant, is there any work done in moving the mass of the piston back and forth. Not turning the wheel or accelerating the engine, just moving the piston.

Yes, the gas does positive work when pushing the piston forwards. However, it also does negative work when the rod pushes the piston backwards and compresses the gas. The sum of the positive work done during expansion and the negative work done during compression is 4kJ.
And as to the other part, Is there a reason why it would be better to use the CM of the rod as the zero point? It too is moving, so why is it not better to choose the lesser of two evils and use the rotation around the piston joint instead.

(You don't need to do this for the question; I'm just responding to clear up any misconceptions.)

You could, and that would give you the rotational energy with respect to that point. However, how do you plan on calculating kinetic energy? If you choose the CM as the reference point, kinetic energy is just 1/2*mv^2, where m is the mass of the entire rod and v is the speed of that point. This is not true for any other point.
 
  • #7
By the way, I assumed that the constant torque was done by an external force on the flywheel, and not by the rod on the flywheel. Is this assumption right?
 
  • #8
Indeed that is correct.
I realized to calculate the energy in the Rod at any point If i was to use the center of mass I would need its horizontal KE, vertical KE and rotational KE.

However, I decided I would use the horizontal KE of the rod at the center of mass, then the rotation around the piston. This makes the calculation easier as I don't have to take into account vertical KE
 
  • #9
Okay, I'm understanding the question better now. I hadn't realized "the constant Torque being applied" referred to an external torque.
ideasrule said:
I think that your initial calculation is correct.
I agree.

Jrak11 said:
I guess I should have been more specific. I meant, is there any work done in moving the mass of the piston back and forth. Not turning the wheel or accelerating the engine, just moving the piston.
No, and we can use the work-energy theorem here:
Wnet = ΔKE​
Since the KE of anything after a complete cycle is the same as it was at the start of the cycle, ΔKE is zero.

That probably makes the following discussion a moot point:

Jrak said:
And as to the other part, Is there a reason why it would be better to use the CM of the rod as the zero point? It too is moving, so why is it not better to choose the lesser of two evils and use the rotation around the piston joint instead.
Jrak11 said:
I realized to calculate the energy in the Rod at any point If i was to use the center of mass I would need its horizontal KE, vertical KE and rotational KE.

However, I decided I would use the horizontal KE of the rod at the center of mass, then the rotation around the piston. This makes the calculation easier as I don't have to take into account vertical KE
I don't think that will work, but I am many years removed from studying this in school. Do you have information from your class lectures or textbook that says the KE may be calculated this way?

I do know that KE can be calculated either by:

(1) Adding the CM translational KE to the CM rotational KE; or
(2) Taking the rotational KE about a fixed point.

Since the piston-rod joint is not fixed (it moves horizontally), method (2) would certainly not work. I'm not sure if adding the CM horizontal KE, as you said, would take care of the problem.
 
  • #10
Rotational Energy of the Rod..

sounds like a movie I might have seen..

Anyways: If we imagine that the rod itself has no mass, all the mass is in the end bolts, connecting the flywheel and piston, respectively. Would you agree that the flywheel bolt rotates, and that the reciprocating piston bolt doesn't? And if we then distribute the mass from the heavy bolts, evenly onto the rod, that then the rotational energy of the rod does not change, as CM is indentical?

I'm not certain, and I've spent some time thinking about it, but I think we calculate half the rod's mass as the rotating mass centered in the flywheel joint. The ellips at rod's CM is far to complex for me to compute. Anyone better?
 

FAQ: What is the Constant Torque Applied in a Simple Piston Engine?

1. How does a simple piston engine work?

A simple piston engine works by converting fuel into mechanical energy through a series of controlled explosions. The process starts with the intake stroke, where a mixture of air and fuel is drawn into the cylinder. Then, the compression stroke compresses the mixture, making it more explosive. The power stroke follows, where a spark plug ignites the compressed mixture, creating an explosion that pushes the piston down. Finally, the exhaust stroke releases the burnt gases out of the cylinder.

2. What are the main components of a simple piston engine?

The main components of a simple piston engine include the cylinder, piston, connecting rod, crankshaft, and valves. The cylinder houses the piston, which moves up and down inside it. The connecting rod connects the piston to the crankshaft, which converts the reciprocating motion of the piston into rotational motion. The valves control the flow of air and fuel into the cylinder and the release of exhaust gases.

3. What is the difference between a two-stroke and four-stroke engine?

A two-stroke engine completes a full cycle (intake, compression, power, and exhaust) in just two strokes of the piston, while a four-stroke engine completes the same cycle in four strokes. This means that a two-stroke engine has a power stroke for every revolution of the crankshaft, making it more efficient but also producing more emissions. On the other hand, a four-stroke engine has a power stroke for every two revolutions, making it less efficient but producing fewer emissions.

4. What are some common uses for simple piston engines?

Simple piston engines are commonly used in various applications, including automobiles, motorcycles, lawnmowers, and small aircraft. They are also used in generators, water pumps, and other small machinery. In addition, they are often used in research and educational settings to demonstrate the principles of combustion engines.

5. How can I maintain a simple piston engine?

To maintain a simple piston engine, regular maintenance is essential. This includes checking and changing the oil, air filter, and spark plugs regularly, as well as monitoring the engine's overall performance. It is also important to follow the manufacturer's recommended service schedule and to address any issues or unusual sounds immediately. Proper storage and use of the engine can also help prolong its lifespan.

Similar threads

Replies
1
Views
1K
Replies
10
Views
6K
Replies
3
Views
2K
Replies
32
Views
7K
Replies
10
Views
1K
Replies
102
Views
5K
Back
Top