Ball against a wall, statics.

In summary, the problem is to find the minimum coefficient of static friction between a ball and a wall so that the ball remains motionless. The solution involves dividing the tension force into x and y components, finding the normal force and friction force, and setting them equal to each other to solve for the minimum coefficient of static friction.
  • #1
philnow
83
0

Homework Statement


Here is a horrible diagram representing the problem:

Picture1.png


The problem is to find the minimum coefficient of static friction between the ball and the wall so that the ball remains motionless.

Homework Equations



torque = r*F

The Attempt at a Solution



I've divided the tension force into x and y components, Tsinθ and Tcosθ respectively. Therefore the normal force (the wall pushing against the ball) is N = Tsinθ. The friction force is = uN = u(Tsinθ).

So now, because the ball is motionless, the two torques must cancel each other out. So Torque from the tension T(t) = (radius)*T and torque from the friction force T(f) = radius*Friction force = radius* uTsinθ. This gives u = (1/sinθ)... but I'm really not sure... also, how do I minimize this u?

Thanks in advance for any help.
 
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  • #2
Looks good to me. Setting the static friction force to equal to its maximum value μN (as you did) will give you the smallest μ. (Generally static friction ≤ μN.)
 
  • #3


I would first like to clarify that the problem statement is incomplete as it does not mention the mass of the ball or the angle of the wall with respect to the horizontal. These variables can affect the solution and should be provided for a complete understanding of the problem.

That being said, I will assume that the mass of the ball is negligible and the angle of the wall is 90 degrees with respect to the horizontal.

In this case, the minimum coefficient of static friction can be found by considering the forces acting on the ball. The ball is in equilibrium, so the sum of the forces in the x and y directions must be equal to zero.

In the x direction, we have the tension force Tsinθ and the friction force uN. Since the ball is not moving, the tension force must be equal to the friction force, so we can write:

Tsinθ = uN

In the y direction, we have the normal force N and the weight of the ball mg. Since the ball is not moving in the y direction, the normal force must be equal to the weight of the ball, so we can write:

N = mg

Substituting N = Tsinθ from the first equation into the second equation, we get:

Tsinθ = u(mg)

Solving for u, we get:

u = Tsinθ/mg

To minimize u, we can see that the value of sinθ is fixed, so the only way to minimize u is to minimize T or increase the weight of the ball. Therefore, the minimum coefficient of static friction is achieved when the tension force is minimized or the weight of the ball is increased.

In conclusion, as a scientist, I would suggest considering all the variables involved in the problem and providing a complete problem statement before attempting to find a solution. Additionally, it is important to clearly define the coordinate system and all the forces acting on the object in order to accurately solve the problem.
 

Related to Ball against a wall, statics.

1. What is the concept of "Ball against a wall, statics?"

The concept of "Ball against a wall, statics" refers to a scenario where a ball is thrown against a wall and remains stationary after impact. This is a common scenario used in physics to study the principles of statics and the forces acting on objects at rest.

2. How is the force of impact calculated in "Ball against a wall, statics?"

The force of impact in "Ball against a wall, statics" is calculated using the formula F=ma, where F is the force, m is the mass of the ball, and a is the acceleration caused by the collision with the wall. This force is equal and opposite to the force exerted by the wall on the ball, according to Newton's Third Law of Motion.

3. What factors affect the ball's motion in "Ball against a wall, statics?"

The factors that can affect the ball's motion in "Ball against a wall, statics" include the initial velocity of the ball, the angle at which it is thrown, the mass and elasticity of the ball, and the friction between the ball and the wall. These factors can impact the force of impact and the direction and speed of the ball after impact.

4. Can "Ball against a wall, statics" be used to study other concepts in physics?

Yes, "Ball against a wall, statics" can be used to study other concepts in physics such as momentum, energy, and collisions. By altering the initial conditions of the scenario, different principles and equations can be applied to analyze the motion and forces involved.

5. What real-life applications does "Ball against a wall, statics" have?

"Ball against a wall, statics" has many real-life applications, including in sports such as billiards and tennis, where understanding the angle and force of impact can help players make precise shots. It is also used in engineering and architecture to calculate the forces acting on structures and design stable and safe buildings and structures.

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