Recent content by BandGeek13

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    Friction Due to Jumping w Parachute

    thanks for all of your help everyone!
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    Friction Due to Jumping w Parachute

    Do you mean the acceleration of the rock towards the ground? haha. Anyway, I'm confused by what you said when finding two different ways of expressing a. If I use the kinematics equation, I get a=6m/s2 So then, Fg=mg =(.5 kg)(a) =(.5 kg)(6m/s2) =3 N And, F=ma F=(.5 kg)(9.8...
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    Friction Due to Jumping w Parachute

    Either F=ma F=(.5 kg)(9.8 m/s2) F=4.9 N Fg=mgh Fg=(.5 kg)(9.8 m/s2)(75 m) Fg=367.5 N Ffriction=Fnet-Fg Ffriction=4.9 N-367.5 N Ffriction=-362.6 N Or \Deltad=v1\Deltat+.5a(\Deltat)2 75 m=0 m/s(5 s)+.5a(5 s)2 a=6m/s2 F=ma F=(.5 kg)(6 m/s2) F=3 N Fg=mgh Fg=(.5 kg)(6...
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    Friction Due to Jumping w Parachute

    Homework Statement A 500 g rock falls out of a 75 m tree. It takes it 5s to parachute to the ground. How much friction is upon it?Homework Equations Fnet=ma Fg=mgh possibly \Deltad=v1\Deltat+.5a(\Deltat)2 and other kinematics formulasThe Attempt at a Solution I tried to find the net force...
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    Understanding the Physics of Music: Frequencies, Overtones, and Resonance

    okay, well it says this in my textbook and we've done classwork using these, but maybe it's just a way of explaining easier? i'm having trouble visualizing this... thank you so much for all your awesome help, DaveC426913 and atyy!
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    Understanding the Physics of Music: Frequencies, Overtones, and Resonance

    I just want to make sure I know these things correctly for an upcoming test, so if anyone can let me know, correct me (especially on the bolded stuff), or give me some extra info, that'd be great! -Music has a constant waveform (sinusoidal), meaning it consists of musical notes with constant...
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    Gravitational Acceleration Problem

    wait! instead of: 69 N [up] = (95 kg)(a) 0.73 m/s^2 = a is it: 1931 N [up] = (95 kg)(a) 20. m/s^2 = a
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    Gravitational Acceleration Problem

    So would it be: F(normal)-F(gravity)=ma F(normal) - mg=ma 1000 N [up] - (95 kg)(9.8 N/kg [down])=(95 kg)(a) 1000 N [up] - 931 N [down] = (95 kg)(a) 69 N [up] = (95 kg)(a) 0.73 m/s^2 = a This seems very low..
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    Gravitational Acceleration Problem

    Homework Statement A 95 kg man jumps, therefore exerting a force of 1000 N on a bathroom scale. The scale is in a motionless elevator in Earth's gravity. What is the man's acceleration? Homework Equations Newton's 2nd Law: F=ma Possibly Fg=mg ? The Attempt at a Solution I tried...
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