Recent content by j1249

Im completely lost and wanted to know how i can start this. There were two cars that got into a collision and hooked bumpers. How can i determine what the speed of the cars was before they hit each other. All i no is that i can measure the skid marks, but like what else? I have to like write a...

so its zero?

meiso, that's what i would like to know to lol :)

okay thanks but how do i figure out normal force in terms of m? it gives me absolutly no values besides the ones in the question

i have tried, but i am completely lost and confused

i believe i no how to solve this question, but only if i had mass, which i dont

yes I'm aware of Newtons laws and the kinematic motion equations but how do i go for solving for Fn so i can solve for Ff? Like, i could do Fg=mg to solve for Fn, but i don't have m so i can't do that equation.

i have no clue where to begin to solve this problem. Can anyone help me out and get me started please and thanks. A hockey puck, sliding on an outdoor rink, has a velocity of 19 m/s forward when it suddenly hits a rough patch of ice that is 5.1 m across. Assume that the coefficient of...

change in velocity divided by the change in time?? right...? lol

well the units of my v-t graph is m/s for velocity and s for time. as for the definition i do not no what you are asking. in my question it only asks me to determine the acceleration for each interval. then draw an a-t graph. so for my first interval i found the area by doing bh/2 so (2)(4)/2...

alright great thanks alot! :)

I am completely lost on how to convert velocity time graphs into acceleration time graphs. so far all i no is to break the velocity graph into sections/intervals and find the area. the answer i get for the area is the scale on my y-axis of my acceleration graph. but what i do not no is what...

Derive formula #5 using any of the other formulas 1. Vav= d/t 2. Aav= V2-V2/t 3. d= (V1+V2/2) t 4. d= V1t + 1/2 a t squared 5. V2 squared = V1 squared + 2ad *note all the Vav, Aav, a and d have a vector sign ontop and d and t always have the triangle representing change in

a steel ball, starting from rest rolls down one slope and up another. it takes 2.5s to reach the bottom of the first slope, at which point its speed is 5.0 m/s. if the magnitutde of the acceleration on the second slope is exactly one-half that on the first slope, how long will it take for the...