- #1
Saitama
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Homework Statement
Which of the following is the solution set of the equation
$$2\arccos(x)=\text{arccot}\left(\frac{2x^2-1}{2x\sqrt{1-x^2}}\right)$$
A)(0,1)
B)(-1,1)-{0}
C)(-1,0)
D)[-1,1]
Ans: A
Homework Equations
The Attempt at a Solution
I start by rewriting LHS in terms of ##\arctan##.
$$2\arccos(x)=2\arctan\left(\frac{\sqrt{1-x^2}}{x}\right)$$
Using ##2\arctan(y)=\arctan\left(\frac{2y}{1-y^2}\right)##, it can be further simplified to
$$\arctan\left(\frac{2x\sqrt{1-x^2}}{2x^2-1}\right)=\text{arccot}\left(\frac{2x^2-1}{2x\sqrt{1-x^2}}\right)$$.
Hence, both LHS and RHS are identical. It can be concluded that they satisfy all values of x in their domain. The domain is (-1,1)-{0} i.e answer is B. But the given answer is A.
Any help is appreciated. Thanks!