The Catch 22 of Newton's 3rd Law

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The discussion revolves around a thought experiment involving a horse and a wagon, questioning how the horse can start moving the wagon if, according to Newton's third law, the forces it exerts are equal and opposite to those exerted by the wagon. Participants clarify that while the horse and wagon do exert equal and opposite forces on each other, the horse also pushes against the ground, which provides an additional forward force. This interaction allows the horse to exert a net force on the wagon, overcoming friction and initiating movement. It's emphasized that forces in Newton's third law act on different bodies, and only forces acting on the same body can cancel out. Understanding the complete set of forces at play is crucial for analyzing motion in this scenario.
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I'm long past the days of general physics, but a friend who's taking it now posed an interesting thought experiment, of which to my embarassment, I was unable to answer! He said, imagine a horse is urged to pull a wagon. The horse refuses to try, citing Newton's third law as his defense: "The pull of the horse on the wagon is equal but opposite to the pull of the wagon on the horse" If I can never exert a greater force on the wagon than it exerts on me, how can I ever start the wagon moving? asks the horse. How would you argue with the horse?

Stupid, I know...but it's driving me crazy! Anyone remember this stuff?
 
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Simple. The horse puts a force forward on the wagon, right? This causes the wagon to exert a force backward on a horse. This force pushes the horse into the ground, causing a net backward force on the earth, and a forward force from the ground to the horse. The force of the Earth on the horse and the wagon on the force cancel, leaving only a net force on the wagon and the earth.
 
Hi. I think you need to bear in mind two things: equal forces acting on bodies does not lead to equal acceleration; and a body accelerates when subject to unbalanced force. There is a Newton's 3rd law force pair between the horse and the wagon, and these are equal and antiparallel, true.

However, there are more forces acting on the horse. As well as being pulled by the wagon, it is also pushing against the ground, a normal reaction that, due to the inclination of the hooves against the ground, yields a force component parallel to the ground away from the wagon. The normal reaction on the wagon is due to its weight and this is pretty much verticle - i.e. negligible horizontal component.

You also have friction acting against the acceleration on both bodies. For the wagon, since it is supported by rotating axles, this is going to be comparitively low. For the horse, whatever the friction is is irrelevant, since it is the total force (normal + friction) that acts on the wagon - i.e. the force the horse exerts on the wagon, that is matched by the wagon itself, includes the horse's friction but NOT the wagon's. The force exerted on the horse by the wagon includes the wagon's friction, but this is lower. Overall, the force is balanced in the horse's favour.
 
pattiecake said:
The horse refuses to try, citing Newton's third law as his defense: "The pull of the horse on the wagon is equal but opposite to the pull of the wagon on the horse" If I can never exert a greater force on the wagon than it exerts on me, how can I ever start the wagon moving? asks the horse. How would you argue with the horse?
Realize that the two forces in Newton's 3rd law always act on different bodies! (In this example the horse and the wagon are the two bodies.) Equal and opposite forces only "cancel" and produce equilibrium if they act on the same body.

To find out how things will move, you need to consider all the forces acting on the body (as others have explained). For example, the horse is also being pushed forward by the ground.
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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