My textbook solution states that 1 & 2 are in parallel and so is 3 & 4 and those 2 are in series. That is, (1 P 2) S (3 P 4). My thinking is such: points A & B are of same potential, say V, C & D are of same potential, say x and E & F are are of same potential, say 0. So I can say that 1 and 3...
While going through the catalogues I started to wonder, typically lower ESR caps cost more, but if I need the cap for DC smoothing , to filter out unwanted AC ripple, then I put that cap across my DC rails +-. Now so far so good.
It's ability to filter out the AC ripple will be directly related...
What I have done:
The electromotive force due to Faraday's Law is: ##\mathcal{E}=-\frac{d\phi(\vec{B})}{dt}=\frac{d}{dt}(Ba^2)=a^2\frac{dB}{dt}=-10^{-4}V.##
In the circuit, going around the loop in a clockwise fashion:
##\oint_{\Gamma}\vec{E}\cdot d\vec{l}=-\frac{d\phi(\vec{B})}{dt}\Rightarrow...
So long story short I have a power supply (DIY) for some time and on the secondary side filter/reservoir capacitors there is a small ripple (about 1v PP) of 50khz (the switching frequency of the PSU).
Aside from others methods that I will implement to reduce this I am thinking of adding a shunt...
In MOSCAP, why does the band stop bending as soon as the Si Fermi level touches either the conduction band (inversion) or the valance band (accumulation)?
With reference to picture, l have an oblique slab of material dieletric in a capacitor. The plates of capacitor are infinite and far. How can calculate E and D in dieletric?
I have watched a number of tutorials on how a capacitor works and I'm still confused about a couple things. Suppose we have a battery who's terminals are connected to the battery. It make sense to me that negative electrons accumulate on one side of the dialectric, because they're attracted to...
I understand that the particle will be polarised according to its dielectric constant and the electric field across the capacitor.
However, since it is similar to an insulator and electrons do not move in and out of the particle easily, the particle will not be charged.
How then will...
With a capacitor with a dielectric with the battery on,
##E_{total} = E_0 + E_i##
##\frac{Q_t}{dC_t} = \frac{Q_0}{dC_0} + \frac{Q_i}{dC_i}##
thus,
##\frac{Q_t}{C_t} = \frac{Q_0}{C_0} + \frac{Q_i}{C_i}##
since in a battery ##V_t = V_0, V_i = 0##, so either ##Q_i = 0## or ##C_i = infinite##
but...
The energy stored in a capacitor is derived by integrated the work needed to move charge dQ from one plate to another. I'm confused on how this energy is the same as electrostatic potential energy, the energy needed to assemble this configuration from infinity. In the case of capacitor energy...
Disclaimer: This is not a repost.
The problem wants me to calculate the force of a p.c. , that is isolated by itself (this p.c. is the only charge this problem starts with in this problem) inside a capacitor, a distance h/4 from the bottom plate.
This is what I have though of so far but I...
Before I can find the force on q I must balance the charges. This problem starts of with -q and q inside the capacitor. I have added image charges on the opposite side of each plate. Would this work?
Consider a simple DC circuit containing a 9V battery, a switch, a 10 kΩ resister and a 100 μF capacitor all in series. When the switch is thrown, it will take basically 5 seconds for the capacitor to reach full charge.
Based on what I have read online, the charge on the above capacitor is...
I tried solving the part (a), and got I =1.82 A for the current value using Kirchoff's law.
Next, I want to use Ohm's law to calculate the voltage at point a.
Va = IR
In this equation, will resistance R correspond to 4.4Ω or 8.8Ω?
How do you determine which resistance to use when solving this...
The following is the question and the solution to the question.
I understand the solution to the part where you find the Ceq and derive Qeq from the equation Q = Ceq*V.
However, I do not understand where V1 = V0-V2 come from.
When calculating the minimum voltage, how do you come up with the...
I considered the capacitor as two capacitors in parallel, so the total capacitance is ##C=C_1+C_2=\frac{\varepsilon_0\varepsilon_1 (A/2)}{d}+\frac{\varepsilon_0\varepsilon_2 (A/2)}{d}=\frac{\varepsilon_0 A}{2d}(\varepsilon_1+\varepsilon_2).##
Since the parallel component of the electric field...
I did a kvl loop and got V + 5Io - 15 Io = 0
So, V = 10Io
Then, substituted dq/dt for Io and q/c for V
I get to dq/dt - 50000q = 0
solving this equation i get q = C x e^50000q (c for constant)
my Io = dq/dt
so Io now is 50,000Ce^50000q
now my Q(0) is 3 x 10^-5
So my Io (0) should be...
My guess is that while the voltage between the two plates is lower when a dielectric is present, the maximum voltage that the capacitor can hold will actually increase because the maximum strength electric field generated by the charges on the two plates will be higher due to the opposing...
The electric field is the one generated by the charge ##+Q## on the inner sphere of the capacitor, which generates a radial electric field ##\vec{E}=\frac{1}{4\pi\varepsilon_0}\frac{Q}{r^2}\hat{r}## which, due to the presence of the dielectric, become...
For applications where the output has considerable ripple or spikes often just using electrolytic capacitors for DC smoothing is not enough because electrolytics themselves have some inductance and series ESR which is mostly the result of their inner structure (wire leads, pins, foil)
I was...
A few days ago, I learned to make an AC to DC converter. One question is troubling my mind. How does a High Pass Filter Capacitor work? Going through some websites I got a sketchy idea.
As the current after passing through the bridge rectifier comes to capacitor, the capacitor starts charging...
Is there any way to measure the capacitance of a capacitor indirectly using a multimeter that does not have the option to measure capacitance directly?
Hello there,
I'm perplexed as to why the capacitor is DC-blocking, but the battery (DC) may charge the capacitor.
I'd never considered it until I recently read it in a book. I honestly have no idea what's going on.
If anyone has any idea why this happens, please let me know.
I've read some...
I am a little lost on the last step of this problem. I get that we want to know how much time elapses for the capacitor to reach 2/3 of its final charge. That is why 2/3Qf is equal to Qf(1-e^-t/RC).
I don't understand how we make the jump to e^-t/Tau is equal to 1/3? and then somehow e^-t/Tau...
Somehow this answer is incorrect , but i realize that even numbers are hipothetical , 45 coulumbs is too much charge , what is wrong in my calculations?
We've observed that an off the shelf electrolyte capacitor (330 μF) charges when it isn't connected to a current supply.
Depending on the surroundings we get something between 10 and 100 mV potential across the capacitor.
Does anybody know what's happening?
Which role plays an additional capacity in a receiver circuit between the antenna and the matching-box part like in this example (found in https://www.frostburg.edu/personal/latta/ee/twinplex/schematic/twinplexschematic.html):
Is it necessary for this receiver circuit or just optional? What...
Hi there,
if a dielectric (capacitor) is described with a constant permittivit eps (or C) and loss-tangent DF, how much energy ist lost when charging the capacitor by 1V?
For example: C=1, DF=0.1.
When charging from 0 to 1V, the lost energy (in J) is ...?
When charging from 1V to 2V, the lost...
Hi there!
I have resolve this basic circuit, but, i have a little questions about.
The first circuit its:
The diode in all voltaje cases act like a switch, so, the courrent of all components and voltage of the resistance its zero. I graph the curve according my interpretation. My question its...
Imagine the two terminal of a *parallel-plate capacitor* are connected to the two terminal of a battery with electric potential difference #V#. If the capacitance of the capacitor is #C#, and the area of each plate is $A$. In this process would the energy lost by the battery and the stored...
Hi , i was just wondering how would i find the current through a capacitor (Series RC circuit)
I found a questions online which asks to find the voltage and the current through a capacitor at 1kHz and 10Khz
Capacitor = 0.01uF
Resistor = 100 Ohms
Voltage Source = 10v
ive done some...
Hey guys! I'm having trouble with the solution that I arrived at.
Through boundary conditions I'm able to determine ##\vec{D}## as $$\vec{D}=-\frac{4Q}{R_0^2}\hat{e_z}$$ (In CGS units)
Trough that I'm able to get the electric field as $$\vec{E}=-\frac{1}{\epsilon(r)}\frac{4Q}{R_0^2}\hat{e_z}$$...
I came across the following explanation from the famous book of Sears and Zemansky which I am unable to understand. I can get the initial part where a positive charge goes to the top plate of C1 since the point a is at a +ve potential causing free electrons to transfer from top plate of C1 to...
why does the voltage of the capacitor eventually go to 0 when discharging the capacitor? I heard that's because "current starts flowing when discharging", but how exactly does that lead to V going down? I know that I = C * dV/dt, but that doesn't seem to help me understand why V goes down (which...
First, I think that I need to calculate the capacitance. It is ## C=\epsilon_0*\frac{l*w}{d}-x*\frac{w*\epsilon_0}{d}+\epsilon*\frac{x*w}{d} ##. After that I should calculate the potential energy. It is ##U=\frac{1}{2}*C*V^2 ##. After that I should take its gradient to get the force. So ##\vec F...
This is not my homework. I took it upon myself to answer a textbook question for mental stimulation. I wanted to know if someone can verify if these were the correct values that needed to be solved for, process, and final answer, and if not, what needed to be considered.
For the initial...
Specifically for part (i) and (ii), I get the rough idea that when the voltage of the AC source is decreasing, the capacitor can discharge to "cushion" the drop in voltage. However, I have some questions about when this occurs.
1. There is an assumption that the capacitor will be charged to...
I have 2 methods, which give 2 different solutions:
Let sigma = charge per unit area
Let plate 1 be the left plate, plate 2 = right plate.
Method 1:
Because they are insulating, consider the electric field at 3 regions; region 1 to the left of plate 1, region 2 between the plates, and region 3...
Hi,
I am trying to find the insulation resistance of a specific capacitor. I've posted on balancing resistors before and got some pretty helpful information. The previous datasheet gave the information in a different manner though. I'm hoping someone can help me decipher the insulation...
The problem is shown below: (I am only asking about part b)
^Above is the problem.
Below is the solution to part b. They have claimed that we can set potential at C = D = u(t), and A=B=0. Why is this claim true?
What I realize:
By applying Kirchoff's across ACDB, Voltage across C1 = Voltage...