On Problem 3.11 for Griffiths' Electrodynamics, there is a question that asks for the critical value between a point charge and a conducting shell, but I don't quite know what they mean by 'critical value' in this context and how I'm supposed to approach this question, the rest of the problem is...
If there is no field inside the conductor, how can there be electric potential?
I think of potential very similar to gravity, as how much energy would be required to move a particle of mass/charge against the gravitational/electric field.
If there is no field at all, how would there still be...
Question 1:
The sphere is at the electric potential of the top plate. As the sphere is small with respect to the capacitor, one can consider the bottom plate to be at infinity and therefore we can use the capacitance formula as C = 4 ∏ε0 R. The charge Q is therefore Q = C (V -0) = C V...
Hi everyone .
if an alternating electric current passes through a piece of straight conducting wire, a proportional magnetic field appears on the orthogonal plane.
what happens to the magnetic field if instead of copper, as a conductor, I use different materials with particular characteristics...
Dear Experts,
When a thin conducting sheet with no charge on is placed at a certain distance from a point charge, does it shield the electric field caused due to the point charge from reaching the other side of the sheet. As an extension of that idea, when a conducting sheet or slab is placed...
First assuming only one sphere at a potential of 1500 V, the charge would be q = 4πεrV = 4π(8.85×10
−12C2/N · m)(0.150 m)(1500 V) = 2.50×10−8C.
The potential from the sphere at a distance of 10.0 m would be V =(1500V)(0.150m)/(10.0m) =22.5V.
I don't understand the reasoning of the...
Since the electric field due to a conducting plate is twice the electric field due to a plastic plate having same charge density, the electric field at the point P will be twice in case of conducting plate and hence it is 20 volt per metre.
Is that correct?
For this part (b) of this problem,
The solution is,
However, would a better explanation be:
As the spheres are conductors, there will be free electrons within and on the surface of the conductors that will be polarized by the external electric field between the conductor. This will decrease...
This is the diagram provided in the question:
The ring is made of conducting material. I was originally asked to find the potential difference between ##a## and ##b##. I did so using the Hall effect (and assuming it would work as per normal in this situation). This got me ##\Delta V = vBl##...
I am having problems understanding point (b) so I would like to know if my reasoning in that part is correct and/or how to think about that part because I don't see how to justify the assumption ##v_y=0\ m/s##. Thanks.
I set up the ##xyz## coordinates system in the usual way with ##xy## in the...
I am building small, simple version of a railgun using 2 copper bars and a couple of neodymium magnets to increase the magnetic field. I have also been trying to mathematically describe the magnetic field created by the conducting rods themselves. I am coming across some trouble when trying to...
What I have done:
(a) If we start at ##R_5## then we have ##\Delta V=-\int_{R_5}^{R_1}\vec{E}\cdot d\vec{l}=-(\int_{R_5}^{R_4}\vec{0}\cdot d\vec{l}+\int_{R_4}^{R_3}\frac{\lambda}{\varepsilon_0}dl+\int_{R_3}^{R_2}\vec{0}\cdot d\vec{l}+\int_{R_2}^{R_1}\frac{\lambda}{\varepsilon_0}dl=-\lambda(...
On the Internet, I have read that the energy doesn't flow in the wire, for example in a very simple electric circuit made of a battery and a closed loop. When one computes the Poynting vector ##\vec S \propto \vec E \times \vec B##, one gets that its direction is towards the center of the wire...
you can treat the center of two conducting sphere's like two point charges. Therefore it should be equal to ##k_e q^2/d^2##, but the answer is greater than ##k_e q^2/d^2##. Can someone explain how? Thank you
As shown in figure below, the electric field E will be normal to the cylinder's cross sectional A
even for distant points since the charge is distributed evenly all over the charged surface and also the surface is very large resulting in a symmetry. So the derived formula should also apply to...
delta q=rho deltaV
rho=dq/dV
dq=rho4pir^2dr
Then integrate dq from 0 to a because A is to be uniform in shell.
Ans: A= 5.3*10^-11 C/m^2
How do we approach these problems? Looking at the answer A seems to be surface charge density. What is A? What is the direction of uniform field E. I don’t...
When I look at the relevant equations, then there is no mention of field for a point on the surface of the shell, so it gets confusing. On the other hand, I feel the radial E will get stronger as we approach the surface of shell and magnitude of E will approach infinity.
I know that metal is a "reservoir" of electrons, whereby electrons can flow out and in easily, so when conducting sphere is rubbed against metals, is there even a resulting charge on the conducting sphere?
Here are the answer choices:
a) F1 = 2F2
b) F1 = 8F2
c) 2F1 = F2
d) F1 = 4F2
e) F1 = F2
I figured that Coulomb's law would tell us the magnitude of the forces are identical, so I answered E, but that was incorrect.
(Screenshot of question attached)
I tried to solve this problem on my own, but I'm not sure whether I solved correctly or not.
it is electromagnetics homework from my Uni, and it is pretty tough for me.
I attached the image of the problem and how I tried to solve this one.
I hope somebody will give some feedback.
I have a question in regards to a neuromuscular device. Can silicone be combined with hydrogel or the rubber silicone encased in hydrogel to form a wrist watch strap combined with a NMES device. If this is possible how would the hydrogel conduct the NMES device and what is the durability of...
Admittedly I found similar threads here already but due to my rather lacking math skills I wanted to go through this myself.
As for the math side, I see various different equations with which this is treated can someone please provide the formulas for calculating B field from a rotating charged...
I'm in an intro E&M class, and I'm trying to distinguish between Motional EMF for loops of wire and conducting plates. This question might be kind of silly, but are Eddy currents pretty much the same thing as induced currents in a loop of wire? More specifically, what I am trying to ask is if...
a) I think you find V by just integrating E in regards to R. Then we integrate from the point of interest, which is a, to the 0 potential which is (R = 2a)?
b) If the same logic as a) applies here as well then we should integrate from the point of interest to the 0 potential. This should be...
figure 1: →
I don't understand how to approach this problem. Basically it asks for the distance r.I think I should use Gauss's law, but I've been thinking about the shape of the gaussian surface and I'm not sure about how it should look or where I should place it. Any help would be useful...
Attached is the subsection of the book I am referring to. The previous section states that the electric field magnitude at any point set up by a charged nonconducting infinite sheet (with uniform charge distribution) is ##E = \frac{\sigma}{2\epsilon_0}##.
Then we move onto the attached...
This news article in Science magazine describes what is becoming known about the different kinds of bacteria that can do this, what is known about how they do it, and how people might make use of the phenomena.
The bacteria conduct electricity through either small nano-filaments sticking out...
Let's say I place a positive point charge inside a hollow conducting sphere. If we take a Gaussian surface through the material of the conductor, we know the field inside the material of the conductor is 0, which implies that there is a -ve charge on the inner wall to make the net enclosed...
The solution to this problem states the electric field is E=σ/ε0. Is that because it's a conducting plate? I know for a non-conducting plate it's E=σ/2ε0. This is a Gauss' Law problem. I know how to derive for non-conducting plate. What's different with conducting plate derivation? Thank you!
Hi,
I think this problem is solved in exactly as a similar problem where the two spheres are very far apart and connected by a very long thin conducting wire. I'm trying to explain this in words, since LaTeX does not seem to work any more (for some reason LaTeX syntax is not replaced by maths in...
i have seen several videos of thyristors but they never really explain the fundamentals
they just say that cause there is a current flowing in there it keeps being on
but why does a transistor then turn off when you remove gate voltage
This is my attempt, i am confused at some points
a. r = 0; The Electric field is 0
b. At r = a/2.00; I verified the answer and it is non zero, but my understanding is that the net charge should be on the surface of the conductor. Hence the charge q1=5*10^-15 C, should go to the surface of the...
It seems to me that one can obtain the required result by using just one neutral sphere and one ground wire.
Let A be the charged sphere and B be the neutral one. Initially ##Q_A=Q## and ##Q_B=0##.
put A and B in contact. As a result ##Q_A=Q/2## and ##Q_B=Q/2##.
ground B, so that ##Q_B=0##...
I am required to find the direction of the electric field on the surface of a grounded conducting sphere in the proximity of a point charge ##+q##. The distance between the center of the sphere and the point charge is ##d## and using the method of images we find that the charge of the sphere is...
I am trying to get more confidence on the direction of current using Amperes law, the problem statement is
Loop1:
My first task was to assign the direction of current. If I wrap around the my right hand fingers in the direction of integration the thumb is pointing up hence Positive Y direction...
I tried to find the the Electric field due to the image charge. So the potential due to the image charge is V=-(pR^2)/√(4R^2-4rRcos(θ)+r^2). When I took the gradient of that in spherical coordinates, I got a mess that doesn't seem to be possible to integrate.
Alright, to start off:
I'm not even sure how this works in the first place. What I do understand is that if they carry current in the opposite direction, using right-hand grip rule, the magnetic field between them will be the same (into the page). Hence using the left-hand rule, I can deduce...
The textbook says
' A conducting sphere shell with radius R is charged until the magnitude of the electric field just outside its surface is E. Then the surface charge density is σ = ϵ0 * E. '
The textbook does show why. Can anybody explain for me?
Summary: Electrodynamics: Conducting Sphere cut in half to form a gap, and a charge q is placed on the first half-sphere. Find all four σ.
A sphere of radius R is cut in half to form a gap of s << R (ignore edge effects) - the first hemisphere is charged with q, and the second hemisphere is left...