Hey i have a heat engine that operates in a Carnot cycle between 354.05K and 711.15K, it absorbs 22415J of energy per cycle from hot resevoir. The duration of each cycle is 0.98s.
First question was to find the mechanical power output...i calculated this and got W = Qh - Qc = 22415 - 11159.43...
I'm not sure if I'm interpreting this question correctly
A heat engine operated between 40C and 380C. Being a real engine, it efficiency is only 60% of that theoretically possible for a Carnot engine at these temperatures. If it absorbs heat at a rate of 60kW at what rate does it exhaust...
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The working substance of a cyclic heat engine is 0.75kg of an ideal gas. The cycle consists of two isobaric processes and two isometric processes as shown in Fig. 12.21 (image above). What would be the efficiency of a Carnot engine...
we have 3 identical bodies of constant thermal capacity, two at 300K and one at 100k. we want to know the highest temperature that anyone of the bodies can be raised by the operation of heat engines.
we already solved this problem in a tute, and we assumed the heat engines were reversible so...
Calculate the ideal (Carnot) efficiency of a heat engine operating between 23.0 degrees and 515 degrees. How much heat would be rejected by the engine if 1.00 x 10^6 calories were taken from the high temperature resivoir.
Would you just use e=1-(T(c)/T(H))?
And for the second part i don't...
for the following question:
a reversible heat engine, opearting in a cycle, withdraws heat from a high-temperature reservoir(the temperature of which consequentyly decreases), performs work w, and rejects heat into a low-temperature reservoir(the tempertaure of which consequentyly increases)...
a firebox is at 750K and the ambient temp is 300K. The efficiency of a Carnot engine doing 150J of work as it transports energy between these constant temperature baths is 60%. The Carnot engine must take in energy 150/.60=250J from the hot reservoir and must put out 100J of energy by heat...
A heat engine operating between temperatures 500K and 300K is used to lift a 10KG mass vertically at a constant speed of 4 meters per second.
Determine the power the engine must supply to life the mass.
I'm having trouble finding an equation that could relate temperature and my other...
when i am calculating the eggiciency of a heat engine i have to convert the celicus to kelvis and used this formula
eff = 1-(T cold/T hot)*100
fro example 302C = 593K 610C = 883K
eff = 1-593/883 = about 32.8% efficient
right ?
thanks joe
ok..Im doing this review packet for Physics B...I did all of a Thermo problem except one part...
Basically an ideal monoatomic gas first expands in an isobaric process, then the pressure is lowered down isometrically, keeping the volume constant, and finally it is returned to state A...