Inclined plane Definition and 822 Threads

I solved for T on m1 and arrived at 6.72. I plugged that value into the ΣFx equation as shown above (pardon my handwriting) and got a mass of 0.88 kg. The online program indicated that I needed to check my expression for tension, noting that the two tensions are heading in opposite directions...

I understand how the diagram below determined the ##x## and ##y## axis for the velocity vectors but I don't understand the gravity vectors. What I don't understand about the gravity vectors is why is ##-mg## in the ##y-##axis equal to ##-mg\cos\theta## and the ##x-##axis is equal to...

This problem was from the chapter on Work and Energy so, I thought of using the principle of conservation of mechanical energy. Clearly, the potential energy of the block decreases by mgh (assuming the block has mass m). This energy should have been converted to kinetic energy, but it clearly...

i tried to solve the problem with the above way then i calculated Fg= mass x 9.8 = 242.06 N FgII= Fg x sin50 =185.4287N so the force required is 185. is this correct?

I was always a little confused about the rolling down of a body, let's say, a sphere. It's know that to body rotate, from the rest, in a referential frame on the ground [inertial], is necessary a friction, that will just act like a medium that transforms kinetic energy of translation into...

The slope of the v^2 vs h graph is g

I tried solving this by assuming the acceleration of the truck and block to be the same so the block would stay on the incline. Also, I would assume truck ma = static friction, block ma = mgsintheta... then I solved for a to plug into 1st equation to get 12990 N. Is this correct? I wasn't sure...

I think that the answer probably will be yes, but i have a question: Well, with respect to center of mass that's right, but if i choose the axis passing through the contact point, the weight force will produce torque, even without the friction.

Summary:: I have done parts a-d but I can't seem to get e correct! A 6.10 kg block is pushed 9.00 m up a smooth 38.0 ∘ inclined plane by a horizontal force of 78.0 N . If the initial speed of the block is 3.20 m/s up the plane. a. Calculate the initial kinetic energy of the block. (found...

the red line is the initial velocity, the grey parabola is the path of the projectile. hi there...I'm kinda stuck at the part b of this problem. I can do part a with no problem. can anybody explain to me how to do the differentiation needed to solve part b?? by explain I mean explain the...

a. I tried to "rotate" the inclined plane so the surface of the inclined plane becomes horizontal h = Vi sin θi . t - 1/2 g cos ∅ t2 and when it falls to the plane, y = 0 so: 0 = Vi sin θi . t - 1/2 g cos ∅ t2 t = (2 Vi sin θi) / (g cos ∅) Is this correct?b. Particle hits the plane vertically...

Hi Smart People, I have spent a lot of time on this and have looked in Reed's and Wallker's applied mechanics but can't find a clear explanation. Calculating the force required when pulling up an inclined plane whether horizontally to the plane or at an angle seems pretty straight forward...

I used work energy theorem between initial top point and point x along the incline(downwards) i got the expression of v then diffrentiated it to get a maxima but it gives me a wrong ans which is 10/6 but the actual ans is 10/3 please tell me what i did wrong

Hi, this is my try: I would appreciate any confirmation or correction . -- Thanks

a=m2g-m1gsinø-m1gcosøu/m1+m2

For the a part of the first problem I did this: mgsinθ < µk*mgcosθ Sinθ < µk*cosθ Tanθ < µk so θ should be less...

Hi If a rigid disc rolls down an incline plane without slipping then the component of weight down the plane causes the disc to accelerate downwards but the frictional force causes a torque which causes the disc to rotate, At the point of rolling without slipping the velocity of the centre of...

This question showed up on my grade 12 physics test. The problem I have with this question is that I did not know the direction that the system would accelerate in, so I just solved as though the mass on the inclined plane would accelerate the system. I expected that if it would accelerate the...

The thing is that my professor said that if the velocity of ##A## is ##400 cm/s##, the velocity of ##B## is ##200 cm/s## because "##B## is connected to two parts of the rope and ##A## is conected just to one part", and he also said that that ##200 cm/s## is the velocity of ##B## with respect to...

I considered the downwards direction and left direction as negative. For ##m_1##, Newton's equations are: ##x) Fr + W_x - T=0## ##y) N - W_y =0## For ##m_2##: ##y) T - W =0## Then, if I replace the data, I get ##T=22.2 N## and then ##m_2=2.2 kg##. With that, for the second question ##m_2=4.4...

Here, I have two doubts 1) if the surfaces are frictionless, then there's no force being applied on the ##x' axis## of ##m_1## except from the weight, so it should be sliding, shouldn't it? So, there's no force that I could apply to ##m_2## to keep ##m_1## in equilibrium since any force that I...

So far I've got E=1/2m(dx/dt)^2+mgh this can be rewritten as (dx/dt)^2=2(E-mgxsin(Θ))/m Would there not be a positive and negative solution? dx/dt=±sqrt(2(E-mgxsin(Θ))/m) or do we discard the negative one? Why would we do so, if that's the case. So far I've only solved the postive solution and...

Homework Statement: A box of mass M=30 kg sits on a ramp which is tilted at angle 13 degrees. The coefficients of static and kinetic friction between the box and the ramp are both 0.12. The box is connected to a spring of spring constant k=9 Newtons per meter. Initially, the box is held in...

a) Describe the motion of the spool: it will roll down the plane, rotating counter clockwise. I am confused when setting up equation of torque. If I take center of the spool as pivot, only the tension of thread produces torque but the direction will be clockwise and it makes the spool will move...

So here is what is going on in my mind: We have a turn that is 400m away from the center of the turn. The faster the car goes, the harder it is for it to maintain its radius. We have a component of the normal force that points towards the center, and static friction which does the same. I...

So we know that all the energy originates from the spring: E(spring) = (1/2)kd^2 As the block moves up the ramp, friction does work on the block over a distance of 2d: W = μmgcos(θ)* 2d So subtracting the work done by friction from the spring energy, gives us the energy left, so we'll set it...

I have attached below the solution provided by the textbook. I understand the whole solution, except when they divide the horizontal component and the vertical component and equate it to the tangent of 30. What seems strange to me is that, while initially the equation for the vertical component...

Hello Got a following problem. 300N Box on a frictionless inclined plane. The plane itself is in the Z-direction. Box is held by a rope AB and a force in the direction Z. Determine the tension in the rope and the force F. The answers to this problem are 104N and 215NMy question is where do i...

I tried to find the force of friction using the the coefficient of kinetic friction with the equation F=nukmgcos Ѳ. Then I made the force of friction equal to the force of pull. I don't know what I'm doing wrong as I'm getting the wrong answer. I have attached a picture of my work.

Here is the question (Qu 9): Here is what I have attempted: assumed that the accelerations are equal, found a value for the acceleration, thus worked out the time taken for A to reach the bottom. then assumed that the tension becomes 0 once A hits the floor, and then worked out B's new...

Since gravity is acting downward, I found the gravity component parallel to the plane, which was g/sin60. I substituted g/sin60 for g into that equation and got D, but the answer should be C.

So here's the problem: A sled slides down a long snow-covered slope that is at an angle θ to the horizontal. Kinetic friction acts on the sled as it slides where the kinetic coefficient of friction between the sled and snow is μk = 0.050. Ignore air-resistance when solving this problem. If we...

Homework Statement The static friction coefficient on an inclined plane is equal to tan(θ). The problem requires me to prove this also works by using an x-axis parallel to the ground rather than parallel to the incline. I understand how to get tan(θ) using the incline as the x-axis, but I don't...

Homework Statement Mass of m1=90kg Inclination is 40degrees. (see the attachment) a) What must be the size of m2 , to hold the system in balance (no movement) ? b)what must be the size of m2 at least, to make m1 move upwards. The static friction coefficient between m1 and the plane is 0.3...

Homework Statement There is an inclined plane which is inclined at an angle of 37° to the horizontal. A projectile is projected perpendicularly to the inclined plane at a velocity of 50m/s such that it strikes a wall kept at the foot of the inclined plane perpendicularly. Find the time taken...

Homework Statement Two identical masses are connected with a rope and are gliding without any friction. Situation given in the picture: Determine after which distance "s" they stop if we have s=0 at t=0 with starting velocity ##v_0## Given: ##\alpha## and ##\beta## with ##\alpha < \beta##...

Homework Statement A car is moving up a rough inclined plane/road of 10 degrees with a velocity of 10m/s. The coefficient of friction is equal to 0.5 and the mass of the car is 10kg. The car brakes. After what distance does the car stop? Homework Equations F=ma v^2=u^2+2as u= initial velocity...

I'm trying to determine the work done by a person as they pull a luggage up a ramp. The ramp has a height of 5 m and the distance the person walks up is 20 m. The weight of the bag is also 10 kg. I am trying to compare the work done by pulling the luggage up a ramp to carrying an equally heavy...

Homework Statement [/B] I got part A and B but in part c , but how to relate period to the equation in part b which is not similar to the cosine function of S.H.M . So i don't know how to obtain period from the equation PS: In part b ,I use mgsin(theta)=-kx and then divided by m Homework...

Homework Statement See picture. Homework EquationsThe Attempt at a Solution I tried at first just doing (1/3)*(48kJ) to get the energy dissipated, but that would i=give me 16kJ

Homework Statement The question says "A block of mass 4kg on a friction less inclined plane at angle of 30° is connected by a cord over massless friction less pulley to a second block of mass 2.3kg hanging vertically. What is the magnitude of acceleration of each block." Given m1 = 4 kg m2 =...

Homework Statement Two blocks of mass m1 = 3.00 kg and m2 = 6.00 kg are connected by a massless string that passes over a frictionless pulley (see the figure below). The inclines are frictionless. Image - https://www.webassign.net/serpse9/5-p-049.gif The inclined plane is shaped like a...

Homework Statement As part of an elaborate prank, a well-greased watermelon (m=4.72 kg) is placed on a ramp inclined with angle θ=27.4° with respect to the horizontal. Because of the grease, the coefficients of static and kinetic friction are µs= 0.560 and µk= 0.392 respectively. The...

Homework Statement If two balls, being identical in volume, but different in density (one ball is made of iron, the other of aluminum) roll down from an inclined plane, which will reach the bottom first and which will cover a larger distance after having reached the bottom? IMPORTANT NOTE...

Homework Statement See question number 1. Homework Equations Work Energy Theorem, work done by all the forces=change in K.E. The Attempt at a Solution I tried solving this question this way, please help me calculate the Work Done by spring here?? I will be thankful for any help!

1. Vo Mass=m 2.So we tried two ways of doing this, one is by taking the y component of the i itial velocity and using that and the other by using the component of its weight parallel to the initial velocity.They give conflicting answers. For the left one it turns out to be t=Vosinθ/g But for...

We have a cube on an inclined plane. The tipping condition is the presence of an unbalanced torque relative to the center of mass (contributing forces are: the normal force and the force of friction). However, is this conditions equivalent to the previous one: The line of action of the force of...

What's the minimal angle of a ramp such that a cube with side 10 cm placed on it will tip over? The coefficient of friction between the cube and the ramp is 0.6. I have given it some thought and I have come to certain conclusions: I think that the cube will tip over once the force of gravity...

Homework Statement A speed of a body of mass 8 kg is 6 m/s in position A. By the time it gets to B, the speed is measured to be 12 m/s. What is the frictional force opposing the motion? The incline is 30 degrees, the height of the ramp is 12 meters. Position A is at the top of the ramp...

Homework Statement [IMG]http://[url=https://ibb.co/b3Emfo]https://preview.ibb.co/gLaEY8/20180527_055248.jpg[ A conducting bar slides down without friction on a pair of conducting rails separated by distance d. Connected to resistor R and there magnetic field B directed upward, perpendicular to...