"An electromagnetic radiation has a frequency of 5 x 10^14Hz
a) (wave in vacuum = 600nm)
b) (wave in water = 440 nm)
c) what is the index of refraction of a medium in which the speed of this radiation is 2.54 x 10^8 m/s?"
so given: c = 2.54 x 10^8 m/s
f = 5 x 10^14Hz...
I can't seem to figure these out guys...maybe I'm missing a few equations too.
1. If light of wavelength 600nm in air enters a medium with index of refraction 1.50, its wavelength in this new medium is...
A. unchanged
B. 900nm
C. 400nm
D. 602nm
---I know that n=c/v...but I don't...
When constructing a Rayleigh Refractometer the formula for the refractive index of a gas at pressure P and temperature T is:
mu(P,T) - 1 = (gamma) P/T
where,
mu(P,T) = refractive index as a function of pressure and temperature
and
gamma = [n(lambda)Ta]/[L(deltaP)]
where,
n = fringe...
When constructing a Rayleigh Refractometer the formula for the refractive index of a gas at pressure P and temperature T is:
mu(P,T) - 1 = (gamma) P/T
where,
mu(P,T) = refractive index as a function of pressure and temperature
and
gamma = [n(lambda)Ta]/[L(deltaP)]
where,
n = fringe...
Hey , I need some indication to solve this problem:
A ray light impinges at a 60 degres angle of incidence on a glass pane of thickness 5mm and index of refraction of 1.54.
the ligth is reflected by a mirror that touches the back of the pane. By how much is the beam displaced compared with...
Given any index of refraction, how would I find a wavelength in that medium? Should I use frequency= c/wavelength? For example, if a piece of glass (medium) has a index of refraction 1.12, what's the wavelength?
I am having a little bit of trouble finding the speed of light in a given medium when you are only supplied with the index of refraction. For example, I was given that n=1.36 in ethanol, and I had to find the speed of sound in ethanol. I know the equation for the index of refraction is n=c/v...
imagine there is a spherical glass object with index of refraction N
is that possible that for some N and angle of incidence A, the light will be total internal reflected forever. In other word, the light will travel within the object forever?
i have been trying to proof it. but i don't know...
Hi guys.
I'm doing this science fair project and I needed to know if there is a substance (any substance!) whose index of refraction can be changed/regulated by applying an electric current (or any other action) to it.
I appreciate all help. Thanks!
given is a graph of n(lambda) vs lambda where n is the index of refraction
N(1000) =1.45
Estimate Vphase and group velocity using the above info.
i know that n = \frac{c}{v_{\phi}} = \frac{ck}{\omega}
i can't simply susbtitute into that above relation because the lambda given is that...
I have input rays into a glass plate and output rays for this glass plate also. How can I prove that they are indeed parallel. I'm thinking all I need to do is extend the inout and output rays, and indicate that they are both 180 deg. Visually, they will appear parallel anyways.
I'm a little confused. My source says the dielectric constant for water is 80. Then I have the equation that gives the index of refraction as n=\sqrt{\epsilon_r} (since it isn't very magnetic). But the index of refraction for water is 1.33. What am I missing?
If
Sin(theta r)/Sin(theta i) is reversed from Sin(theta i)/Sin(theta r) = n, what does this mean? I'm quite confused since I'm doing a physics lab, and the class was told to make a graph where we measured angles with polar paper, pins and plexyglass. Could it possibly the index of refraction...
In this figure the path of the light passes from air to glass. Calculate the index of refraction
n1 = air = 1
n2 = glass = ?
Sin theta 1 = 30degrees
sin theat 2 is = 20 degrees
formula used n2 = n1*sin theta 1 / sin theta 2
sin of 30/ sin of 20 = n2 = 1.46 is this correct
hope the...
Question: One of the beams of an interferometer, as seen in the figure below, passes through a small glass container containing a cavity D = 1.40 cm deep.
When a gas is allowed to slowly fill the container, a total of 230 dark fringes are counted to move past a reference line. The light used...