In mathematics, the triangle inequality states that for any triangle, the sum of the lengths of any two sides must be greater than or equal to the length of the remaining side. This statement permits the inclusion of degenerate triangles, but some authors, especially those writing about elementary geometry, will exclude this possibility, thus leaving out the possibility of equality. If x, y, and z are the lengths of the sides of the triangle, with no side being greater than z, then the triangle inequality states that
z
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{\displaystyle z\leq x+y,}
with equality only in the degenerate case of a triangle with zero area.
In Euclidean geometry and some other geometries, the triangle inequality is a theorem about distances, and it is written using vectors and vector lengths (norms):
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y
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≤
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+
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y
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{\displaystyle \|\mathbf {x} +\mathbf {y} \|\leq \|\mathbf {x} \|+\|\mathbf {y} \|,}
where the length z of the third side has been replaced by the vector sum x + y. When x and y are real numbers, they can be viewed as vectors in R1, and the triangle inequality expresses a relationship between absolute values.
In Euclidean geometry, for right triangles the triangle inequality is a consequence of the Pythagorean theorem, and for general triangles, a consequence of the law of cosines, although it may be proven without these theorems. The inequality can be viewed intuitively in either R2 or R3. The figure at the right shows three examples beginning with clear inequality (top) and approaching equality (bottom). In the Euclidean case, equality occurs only if the triangle has a 180° angle and two 0° angles, making the three vertices collinear, as shown in the bottom example. Thus, in Euclidean geometry, the shortest distance between two points is a straight line.
In spherical geometry, the shortest distance between two points is an arc of a great circle, but the triangle inequality holds provided the restriction is made that the distance between two points on a sphere is the length of a minor spherical line segment (that is, one with central angle in [0, π]) with those endpoints.The triangle inequality is a defining property of norms and measures of distance. This property must be established as a theorem for any function proposed for such purposes for each particular space: for example, spaces such as the real numbers, Euclidean spaces, the Lp spaces (p ≥ 1), and inner product spaces.
see the textbook problem below;
see my working to solution below;
i generally examine the neighbourhood of the critical values in trying to determine the correct inequality. My question is
"is there a different approach other than checking the neighbourhood of the critical values"? In other...
My prof. calls it the triangle inequality. However the wikipedia page with the same this name shows a special case of it, which is ##|x+y|\leq|x|+|y|##, and my prof. calls it the triangle inequality 2. I wonder what the formal name of the inequality in the picture above is. Thanks in adv.
Hi,
This is as part of a larger probability change of variables question, but it was this part that was giving me problems.
Question: If we have ## 0 < x_1 < \infty ## and ## 0 < x_2 < \infty ## and the transformations: ## y_1 = x_1 - x_2 ## and ## y_2 = x_1 + x_2 ##, find inequalities for...
Prove or disprove the following:
There exists $A$ such that for all $a>0$ there exists $b>0$ such that for all $ x$:
$|x-\ x_0|<b$ i mplies. $|\frac{1}{[x]}-A|<a$ where [x] is the floor value of x
Gvf
Hi,
I've been looking at Bells inequality test.
To see if I understand it correctly I'd like to state it in my own words.
Could you please let me know of I have it right?
Thanks
Michael
We have 4 measurements, A,B,C,D
Each measurement is True or False
A is 0 degrees
B is 45 degrees
C is 25.5...
I can solve (i), I got x = -1.6
For (ii), I did like this:
$$(f^{-1} o ~g)(x)<1$$
$$g(x)<f(1)$$
But it is wrong, the correct one should be ##g(x) > f(1)##. Why?
Thanks
Bell's inequality in it's original form is:
|cor(a,b) - cor(a,c)| \le 1 - cor(b,c)
where ##a,b## and ##c## are random variables with values ##\pm 1##, and the correlation is then simply the expectation value of their products, ##cor(a,b)=E[ab]## or as usually expressed ##\langle ab\rangle##...
I am having some trouble find the domain with this function: ##f(x)=\frac{1}{\sqrt{x^2-4x\cos(\theta)+4}}## and ##\theta\in[0,\pi]##.I know that the denominator needs to be greater than 0. So ##\sqrt{x^2-4x\cos(\theta)+4}>0##. I squared both side of the inequality, ##x^2-4x\cos(\theta)+4>0##...
Problem:
Find the set of all harmonic functions ##u(x,y,z)## that satisfy the following inequality in all of ##R^3##
$$|u(x,y,z)|\leq A+A(x^2+y^2+z^2)$$
where ##A## is a nonzero constant.
Work:
I removed the absolute value bars by re-writing the expression
$$-C-C(x^2+y^2+z^2)\leq u\leq...
see attached image, it asks to repesent it in x-graph
constant "a" isn't conditioned.
Do I need to separate it into a few cases of the constant a and represent each in one x-graph?
Correlation between polarization measurements of entangled photons at angles less than 45 are greater than classically statistically possible. No set of hidden variables can be preordained to explain the 75% correlation of photon measurements at 30 degrees and complete anticorrelation of...
First I give detail of what I think I understood so far.
Suppose, there are three angles A, B, C separated by 120° angles. A can measure + (spin up in A direction, we call it A+), and - (spin down in A direction, we call it A-). Same goes for B+, B- and C+, C-.
I have choose A direction to...
Summary:: To prove a conditional statement on a pair of inequalitites.
Mentor note: Moved from technical forum section, so the post is missing the usual fields.
I feel it should be possible to prove this but I keep getting lost in the symbolic manipulation.
Theorem: If a>b implies a>c then...
I got this function in a function analysis and got confused on how to solve its positivity;
I rewrote it as:
$$\sqrt{x^{2}-2x}>x-1 \rightarrow x^2-2x>x^2-2x+1$$
And therefore concluded it must've been impossible... but I'm certainly missing something stupid, since plotting the graphs of the two...
I've been given this answer: to move from negative to positive angles, ##-\theta'=2\pi-\theta##; and to move from positive to negative angles, ##\theta'=\theta-2\pi##. But my question is if there is any way to calculate it in a sequence of inequalities' steps.
If I am being cumbersome, forgive...
The solution from my book:
From $$\frac{3}{x+2}<\frac{13}{12}<\frac{3}{x} \tag1$$
It follows that ##13x<36<13(x+2)##
x<3, i.e. x = 1 or 2. By checking, x=1 is not the solution and x = 2 satisfies the equation.
However, how does the author deduce (1)?
The answer to the above problem is baffling, despite its straightforward nature. I will post the answer later, but here is my solution first.
Solution :
(1) ##2x+1 > x## : In this case, we have ##2x - x > -1 \Rightarrow \boxed{x > - 1}##
(2) ##2x+1 < -x## : In this case, we have ##2x+x < -1...
Summary:: x
Hey, I'm learning calculus and had to prove the following Lemma which is used to prove AM-GM inequality, I had tried to prove it on my own and it is quite different from what is written in my lecture notes.
I have a feeling that my proof of the Lemma is incorrect, but I just don't...
Prove that $\sqrt[3]{\dfrac{2}{1}}+\sqrt[3]{\dfrac{3}{2}}+\cdots+\sqrt[3]{\dfrac{996}{995}}-\dfrac{1989}{2}<\dfrac{1}{3}+\dfrac{1}{6}+\cdots+\dfrac{1}{8961}$.
Given positive real numbers $a,\,b,\,c$ and $d$ that satisfy the following inequalities:
$a \le 1 \\a+4b \le 17\\a+4b+16c \le273\\a+4b+16c+64d \le4369$
Find the minimum value of $\dfrac{1}{d}+\dfrac{2}{4c+d}+\dfrac{3}{16b+4c+d}+\dfrac{4}{64a+16b+4c+d}$.
Note that if we prove problem 4, the proof for problem 5 follows directly. We use properties of logarithms to combine the right hand side of ln into a single logarithm. Then we raise both side of the inequality to a power of e. Which leads us to the desired inequality.
But, when I try to be...
Let $a,\,b$ and $c$ be the side lengths of a triangle. Prove that $\dfrac{a}{\sqrt[3]{4b^3+4c^3}}+\dfrac{c}{\sqrt[3]{4a^3+4b^3}}+\dfrac{a}{\sqrt[3]{4b^3+4c^3}}<2$.
Show that for all $0<x<\dfrac{\pi}{2}$, the following inequality holds:
$\left(1+\dfrac{1}{\sin x}\right)\left(1+\dfrac{1}{\cos x}\right)\ge 5\left[1+x^4\left(\dfrac{\pi}{2}-x\right)^4\right]$
I am reading from Courant's book. He gave an example of the continuity of ##f(x)=5x+3## by finding ##\delta=\epsilon/5##. He then said that ##|x-x_0|## does not exceed ##|y-y_0|/5##, but I don't see how he came up with this inequality.
I know that ##|x-x_0|<\epsilon/5##, and that...
Hello all this is my first post. I am not an engineer, but I wish I was. I have been enjoying watching Dan Gelbart!s YouTube Chanel. His air bearing has me wondering about the relationship and apparent conflict inside ball bearings. How does the ball travel around the shorter distance...
Hello everyone,
I've been struggling quite a bit with this problem, since I'm not sure how to approach it correctly. The inequality form reminds me of the equation of a circle (x^2 + y^2 = r^2), but I have no idea how to be sure about it. Would it help just to simplify the inequality in terms...
In a recent https://mathhelpboards.com/threads/inequality-challenge.27634/#post-121156, anemone asked for a proof that $1-x + x^4 - x^9 + x^{16} - x^{25} + x^{36} > 0$. When I graphed that function, I noticed that in fact it is never less than $\frac12$. If you add more terms to the series, this...
hey so, this is an algebra assignment that we had to do and i really didn't understand the course material that well, but i managed to do the very first steps. anyways i was hoping you guys could help me finish the rest of this table. https://ufile.io/jowwrfj3 or you can see the file attached