L \frac{di}{dt}+Ri=E and we're given i(0)=i_o I,R,E,i_o are constants.
So I rewrite equation as \frac{di}{dt}+\frac{R}{L}i=\frac{E}{L} therefore P(i)=\frac{R}{L}
let \mu(x)=e^{\int \frac{R}{L}dt}=e^{\frac{tr}{L}+C}
multiply equation by integrating factor to get
e^{\frac{tR}{L}}...
Ok, I have a practice exam... My professor gave out a copy with worked out examples. There is one where I don't get his logic at all. I was wondering if you guys could explain it to me?\(\displaystyle (\frac{1}{t}+2y^2t)dt+(2yt^2-\cos(y))dy=0\)
First, he put \(\text{Assume t>0}\)
...
x=c_1\cos{t}+c_2\sin{t} is a two-parameter family of solutions of the DE x''+x=0 Find a solution of the IVP consisting of this differential equation and the following initial conditions:
x(\frac{\pi}{6})=\frac{1}{2} and x'\frac{\pi}{6}=0
So x'=c_2\cos{t}-c_1\sin{t}
x''=-c_2\sin{t}-c_1\cos{t}...
Homework Statement
I'm stuck trying to find out the inverse Laplace of F(s) to get y(t) (the solution for the differential equation):
Y(s) = 1 / [ (s-1)^2 + 1 ]^2
The Attempt at a Solution
I tried using a translation theorem and then apply the sine formula, but the denominator...
Homework Statement
Solve the initial value problem:
dx/dt = x(2-x) x(0) = 1
Homework Equations
Problem statement.
The Attempt at a Solution
Based on the format, I attempted to solve the problem as a separable differential equation:
∫dx/(x[2-x]) = ∫dt
Evaluating to...
Solve the initial value problem y'=2t(1+y), y(0)=0 by the method of successive approximations.
I don't know how to do this problem but I think there's integral involved in it. Please help me. Thanks.
Homework problem for nonlinear dynamics.
Let us write xλ(t) for the solution of the initial value problem
\dot{x} = f(x) & x(0) = λ
where f is continuously differentiable on the whole line and f(0) = 0.
a) Find the differential equation for \frac{∂x_{λ}}{∂λ}(t)
I'm a little confused...
Here is the question:
Here is a link to the question:
Calculus question on differential equations? - Yahoo! Answers
I have posted a link there to this topic so the OP may find my response.
Homework Statement
1.)I want to write a function in MATLAB that contains the 2nd order function:
20*d^{2}x;(dt^{2})+5*dx/dt + 20*x=0 (dampened spring)
-The function should have 2 inputs (time,[initial values]) initial values should be a vector of 2 values
-The function should...
Homework Statement
Find a solution to the initial value problem
that is continuous on the interval where
Homework Equations
I know the equations, but don't want to type them out.The Attempt at a Solution
I got the first part of this question. The part where g(t) = sin(t)
I can not figure...
Homework Statement
The unique solution to the initial value problem
is http://webwork.usi.edu/webwork2_files/tmp/equations/ed/12ad7dca5df62ed3b18f5fbf8c6e871.png
Determine the constant and the function
Homework Equations
Not sure for the second part.
The Attempt at a...
Homework Statement
y''+4y'+6y
y(0) = 2; y'(0) = 4
Homework Equations
\alpha ± β = e^{x\alpha}(cosβx + sinβx)
The Attempt at a Solution
Auxilary equation is r^2+4r+6, which solves for -2 ± i
I get the general solution:
e^{-2x}(c1cosx + c2sinx)
y' = -2e^{-2x}(c1cosx +...
I've had to take diff eqtns now and I'm trying to get my head around Laplace again.. it's been a while. I can't seem to transition to the simplest step of partial fractions, my denominators are tough to figure out.
If someone could point me to the next step that'd be great!
Thanks a lot guys...
Hello. I have gotten as far as to use the Laplace equation with these formulas, but I am having difficulty getting y and x to relate to each other. If requested, I can post my work, but I am sure it is fraught with mistakes. Help is very much appreciated!
x' + 2y' - x - 2y = e^t
x' - y' + x...
Hey everyone, I'm a long-time visitor, it's my first time posting though.
I have a homework problem that is causing me considerable consternation:
(y^3)*(dy/dx)=(8y^4+14)*cos(x); y(0)=C
Oh, and we're supposed to solve the initial-value problem, and then solve for the particular...
Homework Statement
For the space of continuous functions C[0,T] suppose we have the metric ρ(x,y) =sup _{t\in [0,T]}e^{-Lt}\left|x(t)-y(t)\right| for T>0, L≥0.
Consider the IVP problem given by
x'(t) = f(t,x(t)) for t >0,
x(0) = x_{0}
Where f: ℝ×ℝ→ℝ is continuous and globally Lipschitz...
Homework Statement
y'' +4y = 2 delta(t - pi/4)
where y(0)=0 and y'(0)=0
Homework Equations
Laplace transform
Inverse Laplace transform
The Attempt at a Solution
after applying laplace tranform
Y(s)=2e^((-pi/4)*s) / s^(2)+4
as the final answer i have
y(t) =...
Hey,
We haven't properly covered this in class yet, but I am trying to study ahead using online course notes, I manage to finish a few questions but I have gotten stuck here,
The question starts by asking for the solution to the ODE:
y' = 1 - 2xy,
When I solve this using the...
Homework Statement
y''-4y'+4y=0 , y(1)=1 and y'(1)=1
The Attempt at a Solution
Auxiliary equation: r2-4r+4=0
I tried factoring 2 different ways:
(r-2)2=0
r=2,r=2
y1=e2t
y2=y1
y(t)=c1e2t+c2e2t
y(1)=c1e2+c2e2=1 ---eq(1)y'(t)=2c1e2t+2c2e2t
...c2=1/(2e2)-c1 ---eq(2)
sub eq(2) into eq(1)...
Given:
Solve the initial value problem 2(√x)y'+y+4(√x) ; y(1)=2
I am having trouble separating the x's and y's in order to integrate. I keep coming up with:
dy/dx +y/(2(√x))=2...
What do I keep missing here? I am pretty sure you leave the y(1)=2 alone until you are finished with...
Homework Statement
Solve the following Initial Value problem for x(t) and give the value of x(1)
Homework Equations
(dx/dt)-xt=-t , x(0)=2
The Attempt at a Solution
(dx/dt)-xt = -t
(dx/dt) = xt-t
(dx/dt) = t(x-1)
(1/(x-1)) (dx/dt) = t
(1/(x-1)) dx = t dt
Then I integrate...
Thanks for clicking!
So, I've got a problem here that I'm stuck on. I need to find the general solution to
y' = (y3 + 6y2 + 9y)/9
I found this to be
ln|y| + (3/(y+3)) - ln|y+3| = x + c
but I would appreciate it if you would check my work. Anywho, once I have the general solution I...
y' = x
x' = -5y-4x
y(0) = 1
x(0) = 0
after finding the general solution as shown here
http://www.wolframalpha.com/input/?i=y%27+%3D+x%2C+x%27+%3D+-5y-4x
how do you go about applying the initial values and finding the complete solution?
L\frac{dI}{dt}+RI=E
I(0) = I_{0}
Where E is a constant.
I know I need to separate the equation and integrate but I am not quite sure how given all the variables running around...
I don't see how the condition of I(0) = I_{0} helps in any way.
The equation is
y'' + 4y' + 4y = (3 + x)e-x
and initial conditions y(0) = 2, y'(0)=5so from the associated homogenous equation
I think the fundamental set of solutions is {e^-2x, xe^-2x} and so yc would be
Yc = c1e-2x + c2xe-2x
but now I don't know how to get Yp, particular solution or what...
Homework Statement
Determine the solution of the IVP y' + 4ty = 4t, y(0) = 6
Homework Equations
The Attempt at a Solution
p(t) = 4t
g(t) = 4t
μ(t) = e^{\int4tdt}
= e^{\int p(t)}
= e^{\int4tdt}
= e^{2t^{2}}
is this all I need? because i did
\frac{d}{dt}(y * μ(t)) = p(t)...
dy/dt=t^(2)y^(3) , y(0)=-1
I need help solving this
I put the integral (dy/y^3)= integral (t^2)dt
but idk what to do after that or if that's even right
Homework Statement
R(dQ/dt) + (1/C)Q = E_0 e^-t ...Q(0) = 0 and E_0 = a constant
Homework Equations
The Attempt at a Solution
first i rearranged to give:
Q' + (1/CR)Q = (E_0e^-t)/R
next i multiplied all by integrating factor of: u(t) = e^integ:(1/CR) = e^(t/CR)...
Homework Statement
Solve the I.V.P. x2(dy/dx) = (4x2-x-2)/((x+1)(y+1)) , y(1)=1
Homework Equations
The Attempt at a Solution
So far, I got to this:
y2/2 + y = log(x) + 2/x + 3log(x+1) + C
I used the initial conditions to solve for C and got:
C = -1/2 - 3log(2)
Substituting C...
OK, so clearly I am missing something, because I know this is supposed to be a simple problem. It reads:
solve the following initial value problem:
dy/dt=-y+5
y(0)=y_naught
my process is as follows:
dy/(5-y)=dt
integrate
ln(5-y)=t+C
exponential both sides
5-y=(e^t)(e^c)...
Homework Statement
I understand how to do initial value problems but I'm slightly stuck when the initial values are y(0) = y'(0)=0
The question is Solve:
y''+3y''+2y=f(t), y(0)=y'(0)=0 where f(t) is a square wave.
Homework Equations
\Im{y'} =s\Im{y}-y(0)...
Homework Statement
We know that y = Aex is the solution to the initial value problem dy/dx = y; y(0) = A.
This can be shown by solving the equation directly. The goal of this problem is to reach the same conclusion using power series.
Method: Let y be a solution to the initial value...
Homework Statement
3y'' -y' + (x+1)y = 1
y(0) = y'(0) = 0
Homework Equations
Not sure, that's the issue
The Attempt at a Solution
I can't quite get this one using the methods I'm familiar with, and I can't guess a particular solution to neither the equation nor the...
Question:
Find y as a function of x:
x^2 y'' + 8 x y' - 18 y = x^8
y(1)=3, y'(1)=2
Attempted solution:
I found the general equation to be Ax^(-9)+Bx^2+Cx^8.
However when I try to solve the initial value problem for this equation I have 3 unknowns.
I'm given the following DE and initial conditions:
y''=2yy'
y(0)=0, y'(0)=1
I started by doing a reduction of order like so:
w=y', w'=y'', \int w=y=\frac{w^{2}}{2}+c
which then gave me this:
w'=2w(\frac{w^{2}}{2}+c)
w'=w^{3}+2wc
Now I'm stuck on where to go from here. I can't use any of the...
Homework Statement
Find the solution to the initial value problem
dy/dx - y = e^3x
y(0) = 3
Homework Equations
e^∫p(x)
The Attempt at a Solution
Do I treat p(x) = -1?
I(x) = e^∫-1 = e^-x
e^-x(dy/dx) - ye^-x = e^3x . e^-x
e^-x(dy/dx) - e^-x . y = e^2x
e^-x . y = ∫e^2x
y = (2e^2x...
So the question is y" - y' - 6y = e^-x + 12x, y(0)=1,y'(0)=-2
First I found the general solution which came out to be, Ae^3x + Be^-2x
I then Substituted y=ae^-x + bx + c
y'=-ae^-x + b
y"=ae^-x
Then I just compared the coefficients to get a=-1/4, B=-2 and C=-1/6
So I am getting y =...
a 3rd order IVP I am havin trouble with:
y''' -3y'' +2y' = t + e^t y(0)=1, y'(0)= -.25 y''(0)= -1.5
I am using At^2 and B*e^t *t as my Y1 and Y2. Is this correct?
Hey,
we have to solve the following problem for our ODE class.
Homework Statement
Find the solution of the initial value problem
dx/dt = (x^2 + t*x - t^2)/t^2
with t≠0 , x(t_0) = x_0
Describe the (maximal) domain of definition of the solution.
The Attempt at a Solution
Well...
I am having trouble with the below problem:
y'-(3/2)y= 3t+ 2e^t, y(0)= y0. fine value of y0 that separate solutions that grow positively and negatively as t=> infinity.
I found p(t) to be -3/2, u(t) to be e^-3t/2
=> e^-3t/2*y' - 3y/2( e^-3t/2)= e^-3t/2(3t+ 2e^t)
=> -2 -4e^t + ce^...
I need help with an initial value problem,
ty' + (t+1)y= t; y (LN 2)= 1
I divided t and have u(t) as exp Integral of t+1/1 => e^t +t
Multiplied this to the original equation to get
(e^t +t)y' + ((t+ 1)/t) *y *(e^t +t) = (e^t +t)
How can I integrate the above? Are my steps so far...
Homework Statement
Proof that there exist more than one solution to following equation
\frac{dx}{dt} = \sqrt[3]{x^{2}} , x(0) = 0Homework Equations
The Attempt at a Solution
Well, I need a confirmation to my attempt of solution. The one is quite forward:
\Rightarrow x=(1/3(t+c))^{3}
Pluging...
Homework Statement
Find the general solution for the following systems of equations, a solution to the
initial value problem and plot the phase portrait.
--> this is in matrix formx' =
1 2
0 3
all multiplied by x.
also, x(0) =
2
-1
Homework Equations
Determinant, etc.The Attempt at...
Is this problem possible?
Solve the initial value problem
x''(t) + 6x'(t) + 9x(t) = f(t); x(0) = N, x'(0) = M
I get to
X(s)=(F(t)+Ns+6N+M)/(s^2+15)
and don't know where to go from here. Any help would be appreciated.
Hey, I need some guidance on an IVP. In general, how do you proceed on these types of problems when you have only the initial values but no initial equation? For example, I have
x1(0)=1 and x2(0)=0 but that is it. I understand, for example, how to do IVP's in the context of separating...
Homework Statement
solve the initial value problem for u
du/dt= (2t + sec^2(t))/2u also, u(0)=4
Homework Equations
antiderivative of sec^2(t) is tan(t) + C
The Attempt at a Solution
So, the first thing i did was move the "u" with the "u" and "t" with the "t". so the equation looks like...