f(x)=x^3lnx^2
product rule
y'=u'v+v'u
u=x^3
u'=3x^2
v=lnx^2
v'=2lnx^2
f'(x)=3x^2(lnx^2)+2x^3lnx^2)
but answer in book is f'(x)=3x^2(lnx^2)+2x^2
What am i doing wrong?
Can someone explain how the integration of 1/x = ln x
I understand the usual way results in division by zero and that the derivative of ln x = 1/x
So my question is, how is the quantity of area under the curve from 1 to x relate to the
natural log of x
I am not sure how would I work this problem.
Any help would be appreciated.
Estimate
ln 1. 5 = Integral from 1 to 1.5 dt/t
using the approximation 1
2 [Lf (P) + Uf (P)] with
P = {1 =8/8, 9/8, 10/8, 11/8, 12/8=1.5}
Ok really dumb one here for you but for the life of me i can't remember.
first
e^(2lnx) is that equal to x^2
like i said brain fart
thanks for the help guys
Homework Statement
Differentiate:
f(x) = e^(x^3)
Homework Equations
The Attempt at a Solution
lnf(x) = ln(e) + 3ln(x)
1 / f(x) f'(x) = 1 + 3x^2 / x^3
f'(x) = ( e^(x^3) * 3X^2 ) / x^3
However, my book says the answer is 3x^2*e^(x^3).
Any help would be greatly...
the intergral of 1/3x either equals 1/3 ln 3x or 1/3 ln x - i don't know which one is correct though because can't you take the 1/3 out of the intergral and then you get 1/3 ln x - so confused - i should really know this...
Homework Statement
ln ln ln x^3
Homework Equations
The Attempt at a Solution
My teacher was going over the review for the final and this was one of the questions. He said the answer is 1/ln ln x^3 but I don't know how to get that...can someone please help me...thank you!
Homework Statement
Find the derivative of 1 / ln x
Homework Equations
N/A
The Attempt at a Solution
y = 1/lnx
First Attempt:
y' = -1/x/(lnx)^2
y' = -1 / x(lnx)^2
Second Attempt:
ln y = ln (1 / lnx)
ln y = ln 1 - ln x...
This is a small part of a bigger problem, but the part I am having trouble with is finding the derivative of...
ln[sqrt(x^2+y^2)]
I'm sure it is something simple and I remember learning it in Calc I or II but I forgot. Please help remind me! Thank you!
I have some stupid trouble with a simple integration. f(x)=ln(x^(1/2))/x
I try using u substitution. u=ln(x^(1/2)) Then du=1/(x^(1/2)*1/(2x^(1/2))dx=dx/(2x)
Then dx should be 2xdu Then plugging back in I should have intg(2u*du) which would give me (ln(x^(1/2))^2; yet the answer my calculator...
I'm struggling taking the derivatives of anything with ln or e in it. For example the question y=xlnx/e^x,i have the solution and the first step they have is
lny=lnx+ln(lnx)-lne^x. I understand what to do until the last part why is the e^x on top now? If anyone has the time to help me figure...
I was wondering if anyone could help me with a question I was trying to work through today in our A-level math class.
Homework Statement
a. Sketch the graph of y= ln(3x)
b. The normal to the curve at Point Q, with x coordinate q, passes through the origin. Find the equation of the...
So the problem says "Taking ln10=2.30 estimate ln10.3 using differentials."
The only thing I thought of doing was to set an integral from 1 to 10.3 with 1/x being the equation I integrate, but I'm not sure if that is right. Any help?
i need to write a program that sets up a table displaying values of n, sqrt n and ln n from n = 0 - nmax. I've prompted the user to enter a value for integer nmax. but then I've no idea how to make this apply for the value for nmax for my table.
this is what i have so far
//Problem...
Ok, so it's been a while since I've had to integrate anything, much less something like this.
\int \frac{1}{n(1 + \ln{n})^{2/3}} dn
I'm thinking u substition for ln(n) and then du becomes 1/n? But, since the ln(n) is in the denominator of a fraction raised to a power, wouldn't that mess...
ln (x+1) = x-3
i know ln is log base e so the equation becomes:
e^(x-3) = x + 1
and i can rearrange using algebra to get:
e^x = e^3(x+1)
but now I am stuck...how can i separate the x's to solve for it?
thanks.
In ?LON, OM bisects LN.* What conclusion can we draw from this?
a. angle L is congruent to angle N
b. LM is congruent to MN
C. LO is congruent to ON
I think it's B, because OM bisects LN & that's what's left.
i need a lot more help, if anyone is interested in helping me IM me at xstarrlit.
The question is to compute the derivative of
ln (7x+1)^1/2 (3X^2+x)^5
(x^2-3)^3 e^2x
the ln is for both the numerator and denominator
I tried the chain rule and came up with this
1
(7x+1)^1/2 (3x^2+x)^5
(x^2-3)^3 e^2x...
When you intergrate a Ln ax problem does is the answer always 1/x
for example integrate ln 2x
does it equal 1/x or ln 3x and so on
For some reason when i work it out on paper or my calculator it comes out to 1/x and I just don't think its right. I think I am just being catious since...
I've had troubled sleep because of this...:cry:
I tryed a lot and got this...
Can you spot any mistakes or give me hints on how to approach this
Thanks
The question is: for a Gaussian distribution what is the mathematical relationship between the FWHM and the standard deviation.
The equations I'm using are:
N(x) =\frac {\ a}{2}
N(x) = Ae^- \frac {\ (x-x_2)^2}{2 sigma^2}
I equated the equations and started to solve for x. I know you...
Hey there, I'm trying to work out all the solutions of z for ln(z)=-1. I let -1=ln|z| so then I took exponentials of both sides so I had e^(-1)=|z| so 1/e would equal z. I wasn't sure about having z also equal to -1/e, because since ln(z) = ln|z| + iarg(z) then for z=-1/e then the arg (z)...
Summations and calculus gives me fits so please verify my results on these 2 issues:
1. Z = summation ( exp ( - B*E(s)) ) where the sum is over s
d/dB of ln(Z) = d/dB (ln (exp(-BEo) + exp(-BE1) + ... exp(-BEn))
= (exp(-BEo) + exp(-BE1) + ... exp(-BEn))^-1 +
(-E0*exp(-BEo)...
Hi all.
For any of you who have done differential calculus, I need a little help with a problem involving natural logarithms.
The question asks to differentiate y = ln x from first principles . It says "use the definition of the Euler number, namely e = lim(n->inf.) (1+1/n)^n.".
First...