Magnitude Definition and 1000 Threads

Finding the apparent magnitude before the explosion is straightforward and easy.$$m= M + 5log(\dfrac {d}{10}) = 29.19$$ Idk how to find it after explosion ... The change in apparent magnitude should be calculated using ##-2.5log(10^9)## , Idk why this formula is true and where it came from ...

I want to find ##\|G\|_\infty##, the solution in the pic uses the Bode plot. But to tell you the truth I am worse at drawing it. So basically what I thought is I want to find: ##|G(i\omega)|=1/\sqrt{(25−\omega^2)^2+9\omega^2}##. So basically I much prefer to find the minimum value of what is in...

This post parallels a post I made in electrical engineering regarding the S plane. I thought I would post an equivalent in basic physics. So, given a graph of velocity vs time we have on the vertical axis meters/sec and the hormonal axis just meters. Given a plot of V vs t we know the area...

In the S plane we have a real component, usually called sigma, and the imaginary component, jw, in radians/sec. The real component is sometimes called nepers per second, with nepers being dimensionless. However, if we draw a vector in the s-plane, say s - s1, in polar form, what are the units...

In my working i have; For a) ##\tan 55^{\circ} = \dfrac{450}{R}## ##R = \dfrac{450}{\tan 55^{\circ} }= 315 N## part b) no problem here ...horizontal to left. c) This is where my real doubt is, i have using sine rule; ##\dfrac{9.8}{sin 55^{\circ} }= \dfrac{a}{sin 35^{\circ}}## ##a =...

In my working i have, the attached. My question is Why is the Reaction force not being considered here, My equations are; Frictional force = ## 30\cos 50^0 - 20\cos 40^0 = (19.28 - 15.32)N = 3.96N## The direction will be downwards.

Going through this ( Revision) A salways your insights are quite helpful. I would like to go through all these questions; i will start with (5), ##\left( \dfrac {x} {y} \right)## = ##\left( \dfrac {10 \cos 40^0} {10 \sin 40^0} \right)## + ##\left( \dfrac {4 \cos 150^0} {4\sin 150^0}...

My approach is as follows, let ##D## be driving force and ##F## the force resisting motion, then ##D-F = 850 × 0.3## ##D = 250 + 255## ##D = 505## Also, Force parallel to the road is given by, ##F_1 = 8500 \cos 78^0 =1767.24 N## Therefore, the magnitude of Driving force is given by, ##F_1 +...

Hello, My textbook offers the following transfer function as an example. It then goes on to explain that the following equations represent the magnitude and phase shift of the transfer function. However, I am having some difficulty jumping from the first equation to these equations. From...

Cornwall shaken by 2.7 magnitude earthquake https://www.bbc.com/news/articles/c724le759lro That's not a significant earthquake, unless one's house is near the epicenter. Residents in Helston, Penzance and Camborne reported feeling the tremors. Some of my ancestors were from that area, and I...

https://www.msn.com/en-us/weather/topstories/rare-5-3-magnitude-earthquake-jolts-west-texas/ar-AA1jBhJ8 M 5.2 - Coalson Draw, Texas https://earthquake.usgs.gov/earthquakes/eventpage/tx2023vxae/executive 2023-11-08 10:27:49 (UTC) 31.622°N 103.982°W 7.4 km depth There was an unusal set of...

So i found the magnitude which is (-1)^2 + (-2)^2 = P^2 = Sqrt(5) Then I used the inverse tan function to find the angle (direction) theta = arctan (-2/-1) = 63.8 degrees Im confused with my 63.8 degrees since the angle in the graph looks greater than 63.4 degrees I subtracted 180 by 63.8 and...

At first I thought that this force vector ## \vec F = 3 \hat x + 2 \hat y ## is a function of ## x ## and ## y ##, which is to say that its magnitude and direction vary with the x and y positions, but this is not so, right? It's just a force with a constant magnitude and direction. And I can...

I've no idea how to solve this problem. The sign of the charge is not mentioned, so I'm assuming the charge is "+". The charge exerts an outward electric field. Since two lengths of the right-angle triangle are given, I use the Pythagorean to find the hypotenuse, which is the distance between q...

There are two identical spheres with the same charge that are the vertices of an equilateral triangle. ##+3 \mu C## will exert an outward electric field, which is drawn in the FBD below (see the attached pic), Since the horizontal force components (1x and 2x) are equal and opposite at point P...

There are three charges with +1 μC and −1 μC, are placed at the opposite corners of a cube with edges of length 1 cm, and the distance from P to B is 1cm 2. I labeled them as A, P, and B, which is shown in the diagram below. Since we need to find the magnitude of the charge at point P and the...

Good Morning (And apologies if this is not the right forum -- it is not a homework problem.) On the one hand, a vector is an arrow and a tail: it has magnitude and direction. It is used to describe direction, forces, acceleration, etc. However, there are more mathematical definitions: a...

Hello! I am trying to simulate the following experiment. It is a counting experiment where the probability of getting an event after a given trial is given by: $$P = 2\left(\frac{a}{x}+\frac{b}{c}\right)^2\left(1-\cos\left(\frac{\pi x}{x_0}\right)\right)$$ where, ##a = 4\pi##, ##b = 2000\pi##...

[mentor's note - moved from one of the homework help forums] Homework Statement:: It's a question. Relevant Equations:: Vector calculus. Is it true to say that in one dimension I can show vector quantities using ±number instead of a vector? ± can show possible directions in one dimension and...

Member CB of the vise shown exerts on block B a force P directed along line CB. Knowing that P must have a (1237) N horizontal component, determine (a) the magnitude of the force P, (b) its vertical component i don't get it what the "N horizontal component"

Okay so I am a little confused as to where I made a mistake. I couldn't figure out how to program Latex into this website but I attached a file with the work I did and an explanation of my thought process along the way.

I understand that it is a 2D momentum problem with an elastic collision; Looking at the vector diagrams below, I notice that the velocity vectors initial and final in the y direction are in the same direction, indicating that momentum does not change, whereas the velocity vectors initial and...

I got to the quadratic equation of the motion where: 4gt^(2) - g(delta t)t - g(delta t) = 0 and tried to solve for t. In this case, we would take the positive discriminate since we are dealing with the passing of time. t = ((sqrt(17) g(delta t)) + g (delta t)) / (8g) However, this is the...

For this part(b) of this problem, how is the magnitude of the total electric force zero? I thought it would be: If they asked for the total electric force, then I would have said zero because the two electric force vectors cancel. Many thanks!

Solving with Torricelli I get Vt = 6x10^-3 m/s Solving with Bernoulli I get Vt = 6x10^-4 m/s, a whole order of magnitude smaller. How can it be correct? I know that Torricelli is an approximation, but the solution given by the book uses Torricelli which doesn't seem right to me.

Question regarding finding the magnitude of Torque of a system of two masses attached to a rod rotating at angle of θ degrees with respect to a vertical

V^2= u^2 +2gh

My attempt has been attached.

So far, I've only attempted the first number: F = (4kg) [(-4+2t)-0]/t ? Been thinking how to cancel out the time, but I really have no idea how to proceed. Was I supposed to cancel it even? Can someone please help and tell me how you would answer this? (And maybe show a solution as well so I...

https://ibb.co/jG6n0jZ The 15 is fine as this is clearly his overall magnitude but then v2 is equated to the horizontal velocity rather than the magnitude.

https://www.bloomberg.com/news/articles/2022-03-16/7-3-magnitude-quake-hits-north-japan-tsunami-alert-issued

Summary:: In a mass-spring system they talk about 'magnitude of dynamic force', what is meant with that? Hi! In a mass-spring system I read about the term: "magnitude of dynamic force" (see sketch). What is meant with that? I the end this is used to determine the accuracy as I understand it...

Please could I ask for help with the following: Here is my diagram, I show the rod displaced from the sphere so as to label the internal forces acting on each of the rod and the sphere: In the diagram below I have added the line through DE at angle ꞷ the the horizontal, and a few other...

Clearly if ##F = 0## and ##\tan\theta > \mu_s##, then using the above equations for ##f_s## and ##n##, we get ##f_s > \mu_s n## so the block will slip. However, it seems that as long as the force ##F## is directed to the right with a certain minimum magnitude, namely ##\frac{\tan\theta -...

I tried using the equations above, but I wasn't really able to come up with an intuitive explanation. From my understanding, the electric field vector only varies in the x-y plane while the magnetic field vector only varies in the z-y plane. Also, both vary sinusoidally and both reach extrema...

I think I have the answer, but when I calculate it out, I'm off by at least an order of magnitude. My process goes like this: The (looked up) specific activity of Ca-49 is ##1.63*10^7 TBq/g##, which is ##1.63*10^{16} KBq/g## The activity of the sample after 5 minutes rest is ##166KBq##, per...

So I was watching a YouTube video preparing for a quiz on Wednesday, and I saw something that I would like clarification on. I'm pretty sure I understand what is being explained, but I just want to confirm. The figure above is associated with the problem at hand. So I understand that to get the...

I have attached the work to this problem and although it has different parameters than what I have listed in my post the basis to solving the problem is the same. I am confused on why this rectangle in this problem is considered to b in the j unit vector direction. Is it because its face will...

i have tried V=Vi - (g*t) with an answer equals to 4 as well as d=Vi(t) + 1/2 a t^2 with an answer equals to 19 my final asnwer was 1.43 and it was still wrong i used formula a=v/t v=14 t=10 i divided 14/10 to get 1.4

Hello, I solved this problem two ways and got the same value for the magnitude but different values for the angle. I am wondering which is correct. I showed my work, so I hope someone can tell me if one method is just invalid.

My notes says that the geometrical meaning of $$|\vec v \times \vec w | $$ is the perpendicular distance from point ##V## to line passing through ##O## and ##W## (all vectors are position vectors) $$|\vec v \times \vec w | = |\vec v| |\vec w| \sin \theta$$ From the picture, the perpendicular...

Tried this, but not sure how am I supposed to square the whole equation and then square root it since this will inevitably give me imaginary values. Am I supposed to ignore the imaginary values? Also, how can I find out the phase in this case? Usually, it's taking the exponents but in this case...

Error Vector Magnitude is widely used in the telecommunication industry to assess the performance of the users. In the given formula, Sr(n) is the received symbol and St(n) is the ideal symbol. N is the total number of symbols received. I have a Multi-User MIMO system simulation where there are...

The only explanation that I have seen in textbooks is that since the outer spherical shell is symmetrical relative to internal charged spherical shell so field every where on the outer shell is same in magnitude at every point on it. I can understand that electric field needs to be...

k(q_1-q_2)/(R^2+x^2)^3/2

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I have to perform a calculation on my data. Here is an example of data from just one time step (data from other time steps would appear as additional rows). X Y Z Total 2 2 1 3 Total = SQRT(X2 + Y2 + Z2). The calculation I have to do is: (N • N), where "N" is an average. I tried...

P is = to 7 and I don't know how to get the absolute magnitude please help.

I used a couple ways to do this question, but I got neither correct. Can someone help, please? Thank you. 1. E= V/r = 700 / (60*10^-3) = 11667 (very far from the given answer) 2. E = (-kQ/r)⋅ dr = kQ/r^2 = kQ/ [( 1/20/ 10^-3)^2 - (1/80/10^-3)^2] (For this method, I stuck...