In elementary algebra, the quadratic formula is a formula that provides the solution(s) to a quadratic equation. There are other ways of solving a quadratic equation instead of using the quadratic formula, such as factoring (direct factoring, grouping, AC method), completing the square, graphing and others.Given a general quadratic equation of the form
a
x
2
+
b
x
+
c
=
0
{\displaystyle ax^{2}+bx+c=0}
with x representing an unknown, a, b and c representing constants with a ≠ 0, the quadratic formula is:
where the plus-minus symbol "±" indicates that the quadratic equation has two solutions. Written separately, they become:
x
1
=
−
b
+
b
2
−
4
a
c
2
a
and
x
2
=
−
b
−
b
2
−
4
a
c
2
a
{\displaystyle x_{1}={\frac {-b+{\sqrt {b^{2}-4ac}}}{2a}}\quad {\text{and}}\quad x_{2}={\frac {-b-{\sqrt {b^{2}-4ac}}}{2a}}}
Each of these two solutions is also called a root (or zero) of the quadratic equation. Geometrically, these roots represent the x-values at which any parabola, explicitly given as y = ax2 + bx + c, crosses the x-axis.As well as being a formula that yields the zeros of any parabola, the quadratic formula can also be used to identify the axis of symmetry of the parabola, and the number of real zeros the quadratic equation contains.
Hey guys,
I've tried to do this quadratic question using the formula but can't seem to get it and don't know if its right or not.
x= -b+-√b^2 – 4ac / 2a
a= 37.5
b= L
c= L^2
Need to find X the sub X into find L in metres.
Thanks in Advance
Umm... I guess I don't remember this from algebra, but I have a rather basic question.
Let's say you have the expression,
f(x) = 4x^2 + 5x + 1
And we want to find the roots.
So,
\frac{-5 \pm \sqrt{5-4(4)}}{2(4)}= \{ \frac{1}{2},-1 \}
Now, if we plug these into f(x) we have...
I'm learning equilibirum in class, but I am stuck on this question. DOes anyone how how to do this problem? I use the quadratic formula but end end with answers A and B, but the correct answer is A. Can someone show me step by step how to do this problem? thanks
9. At a certain temperature...
A large dealership had been selling new cars at $6000 over the factory price. Sales have been averaging 80 cars per mouth. Because of inflation, the $6000 markup is going to be increased. The marketing manager has determined that, for every $100 increase, there will be one less car
sold each...
http://www.mste.uiuc.edu/users/exner/ncsa/quad/
There's another way of writing the quadratic formula...but how do I derive the 2nd formula using the 1st one? I've tried for hours and I can't get it. I would really appreciate any help.
I know this is a basic question, but can someone please help me with WHEN to use the quadratic formula, i just wondered, can it be used on any quadratic?
Quadratic formula help ...
Heres the question ... your help is greatly needed and appreciated ...
Markita wants to fence a rectangular plot of land along side the shore of a lake. Only 3 sides must be fenced, since the lake will form teh lake will form teh fourth side. Markita had 100m of...