hey, just a really quick question, any help wud be great,
is it possible to simplify this radical further?
p = sqrt root (6/70q^2)
thx in advance for help.
This is probably easy for everyone on this forum but me. Can someone please explain this to me.
I need to simplify this:
(sqrt(x) - 4) / (x - 16))
am I on the right track by doing it this way...
(sqrt(x) - 4) / (sqrt(x) - 4) (sqrt(x) + 4) ...then cancel the (sqrt(x) - 4) in the...
... or would it be inert to it as well? And if this depends on the particular gas and radical, could you give an example of when a reaction would/wouldn't occur?
Quadratic equation and Radical function!
Please help with these two problems!
1) a) Find a radical function where f(4)=0 and f(16)=6
b) Find a radical function where f(4)=0 and f(2)=2
2) a) find a quadratic function where the vertex is (3,-1) and has a vertical intercept of (0,8)...
In attempting to prove an algebraic identity in physics, I found that my proof was simplified in appearance if i used an operation
a@b=a + b - ab
By flipping through a book on ring theory, I found that this is called a "circle composition operation", and it is used in one definition of the...
Simplify
sqrt(11+sqrt72)) + sqrt(11-sqrt(72))
better picture here
http://members.rogers.com/agentj/images/math.jpg
I don't know where to begin for this one, but apparently my calculator says the answer is 6 :redface:
Simplify (y^-3 - x^-3) / (xy^-1 + x^-1y + 1)
better picture of it here
http://members.rogers.com/agentj/images/math2.jpg
I tried flipping the variables with negative exponents to the numerator and denominator, but then had no idea what to do next :frown:
radical “Selfish Biocosm”
Anyone heard of this?
http://www.biocosm.org/
PDF link with the foreword and outline.
http://www.biocosm.org/BIOCOSMRoman.pdf
Looking for theories that describe "time" The more radical the better.
I'm trying to start up some interesting conversations about time at
http://thinkbling.com/forum
Please post any comments that you may have and want shared there.
For now this will only be for this category.