Statics is the branch of mechanics that is concerned with the analysis of (force and torque, or "moment") acting on physical systems that do not experience an acceleration (a=0), but rather, are in static equilibrium with their environment. The application of Newton's second law to a system gives:
F
=
m
a
.
{\displaystyle {\textbf {F}}=m{\textbf {a}}\,.}
Where bold font indicates a vector that has magnitude and direction.
F
{\displaystyle {\textbf {F}}}
is the total of the forces acting on the system,
m
{\displaystyle m}
is the mass of the system and
a
{\displaystyle {\textbf {a}}}
is the acceleration of the system. The summation of forces will give the direction and the magnitude of the acceleration and will be inversely proportional to the mass. The assumption of static equilibrium of
a
{\displaystyle {\textbf {a}}}
= 0 leads to:
F
=
0
.
{\displaystyle {\textbf {F}}=0\,.}
The summation of forces, one of which might be unknown, allows that unknown to be found. So when in static equilibrium, the acceleration of the system is zero and the system is either at rest, or its center of mass moves at constant velocity. Likewise the application of the assumption of zero acceleration to the summation of moments acting on the system leads to:
M
=
I
α
=
0
.
{\displaystyle {\textbf {M}}=I\alpha =0\,.}
Here,
M
{\displaystyle {\textbf {M}}}
is the summation of all moments acting on the system,
I
{\displaystyle I}
is the moment of inertia of the mass and
α
{\displaystyle \alpha }
= 0 the angular acceleration of the system, which when assumed to be zero leads to:
M
=
0
.
{\displaystyle {\textbf {M}}=0\,.}
The summation of moments, one of which might be unknown, allows that unknown to be found.
These two equations together, can be applied to solve for as many as two loads (forces and moments) acting on the system.
From Newton's first law, this implies that the net force and net torque on every part of the system is zero. The net forces equaling zero is known as the first condition for equilibrium, and the net torque equaling zero is known as the second condition for equilibrium. See statically indeterminate.
A physicist who does research in statics is called a statician.
Homework Statement
Homework Equations***i posted the questions and my free body diagrams below
The Attempt at a Solution
Hi. I'm trying to analyze this structure particularly at points C and B.
when drawing the free body diagram, i notice there would be pin forces on C as well as B. Also...
Homework Statement
Homework EquationsThe Attempt at a Solution
I am getting 5/2 m as the answer.
(not a choice)
FR = -F1 -3F1 = -4F1
Mo = -F1(1) - 3F1(3) = -10F1
Mo = FRx
x = -10/-4 = 5/2
Homework Statement
Homework Equations
The Attempt at a Solution
I've spent so long trying to solve this system of equations with my calculator that can do this for me. But, somehow , i still don't get it.The equations i got are:
1st diagram
Fc - Nb =0
Nc -0.3Nb -300=0...
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Homework Equations
Trying to find the reaction forces at E. But, I am kinda confused about drawing the free body diagram for each member. I know that member AD and CB are two force members. What is wrong with my free body diagram then?
The Attempt at a Solution
i...
Homework Statement
"A beam of mass M = 280kg and length L = 2.2m is attached to a wall with a hinge (at a 90 degree angle to the wall, sticking out horizontally), and is supported at the other end by a wire making an angle of 30 degrees with the horizontal beam.
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Homework EquationsThe Attempt at a Solution
[/B]
the force resultant = (100i +620j +800k) = 379 N
moment result is (100i-620j+800k) = 1017 which is not correct!
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Homework Statement
Part C ) help
Homework Equations
So far..
Moment resultant = 1800i +3200k , magnitude = 3070 N*m
Force resultant = 500i +300j + 800k , magnitude = 990 N
The Attempt at a Solution
For the location, I'm not getting x = 1.16, y =2.06.
Instead , I am getting
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<< Mentor Note -- Thread moved from the technical forums, so no Homework Template is shown >>
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Homework Equations
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https://imgur.com/a/AGJaN
It's a project so not a textbook question.
The Attempt at a Solution
Given in imgur picture.
[/B]
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All data are in the image uploaded
Homework Equations
I don't know how to deal with two confounded loads
The Attempt at a Solution
I really need fast replies thnak for your attempt
Homework Statement
Homework Equations
deformation=(force*length)/(elastic moduli*area)
The Attempt at a Solution
and
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Homework Statement
Pin A and C are the same, however in the solution manual it shows that C does not have a y component. Why is that?
Homework EquationsThe Attempt at a Solution
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Problem image: https://prnt.sc/gvhjso
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The angle at the bottom is 25 degrees
Homework Equations
Springs Parallel;
keq = k1 +k2
Sum Forces = f1 + f2
x = f1/k1 = f2/k2
Springs Series;
1/keq = 1/k1 + 1/k2
Sum x = x1 +x2
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Homework Equations
P = pgh
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Hi, I'm having trouble with my first mechanics assignment and I'd appreciate some help.
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Hi, I'm having trouble with my first mechanics assignment and I'd appreciate some help.
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Homework Equations
Basic Trigonometrics
The Attempt at a Solution
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Homework Equations
$$\vec M = \vec r \times \vec F$$
The Attempt at...
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I'm trying to solve for this problem below.How would you be able to get the force in member ID and GC? Find the reaction forces in member AFGH
Homework Equations
∑M = 0
∑[F][/y] = 0
∑[F][/x] = 0[/B]
The Attempt at a Solution
I dismembered all of its parts but no matter...
Homework Statement
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The board shown below is being held in equilibrium in the vertical plane by three smooth rods at A, B, and C
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Homework Equations
Moment = f*r
Here's a diagram
The Attempt at a...
Homework Statement
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[/B]Homework EquationsThe Attempt at a Solution
[/B]
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Determine all member forces and state if they are in tension or compression, in particular I am looking for member AE and AB[/B]
Homework EquationsThe Attempt at a Solution
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