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What Did I Do Wrong? Analyzing y = x tan x
y = x tan x y' = tan x + x*sec^2(x) y'' = sec^2(x) + d/dx (x*sec^2(x)) = ... + (d/dx(sec^2(x)) + sec^2(x)) = ... + (2secx + sec^2(x)) = 2sec^3 x + sec^4(x) what did I do wrong?? in book it says y'' = something else.
PrudensOptimus
Thread
Oct 9, 2003
Tags
Tan
Replies: 3
Forum:
Calculus
K
What are Sin hx, Cos hx, Tan hx in Mathematics?
sin hx, cos hx, tan h x... What are they? What does the "h" mean here? Any explanations or websites would be appreciated. :smile:
KLscilevothma
Thread
May 20, 2003
Tags
Cos
Sin
Tan
Replies: 12
Forum:
General Math
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