Dear Forum,
My goal is to rotate several points on a sphere by a theta and phi. For example, I have a sphere where the elevation is theta (90 to -90) and the azimuthal is phi (-180 to 180). I have the following points on the sphere:
theta = [45 45 45 45]
phi = [-180 90 90 180]
This generate...
I am not sure what I am doing wrong but dot product of a and b =/= |a||b| when I am trying to calculate it. Theta = 0:
dot product(a and b) = ax*bx + ay*by
|a||b|= sqrt((ax^2+ay^2)*(ax^2 + by^2)) = sqrt((ax*bx)^2 + (ax*by)^2 + (ay*bx)^2 + (ay*by)^2) =/= ax*bx + ay*by
What am I doing wrong?
This is a past paper question...
find the solution here from ms
...wawawawawa...it took a little bit of my time because i was only thinking of taking limits...then realized that i was wrong as we have to remain with ##2θ##...i later realized that for small approximations, ##\cos θ≈1-\frac...
As the summary says we have ## f(x) = x^n - \theta \in \mathbb{Q}[x] ##. We will call the pth primitive root ## \omega ## and we denote ##[\mathbb{Q}(\omega) : \mathbb{Q}] = j##. We want to show that the Galois group is generated by ##\sigma, \tau## such that
$$ \sigma^j = \tau^p = 1...
For the displacement, how do I figure out the angle theta between the points? And how does the speed at which the string retracts affect the centripetal force?
For $-\dfrac{\pi}{2}\le \theta \le \dfrac{\pi}{2}
\quad |\sin{\theta}\ge 1|$ is true for all and only the values of $\theta$ in which of the following sets
$a.\ \left\{-\dfrac{\pi}{2},\dfrac{\pi}{2}\right\}
\quad b.\ \left\{\dfrac{\pi}{2}\right\}
\quad c.\ \left\{\theta | -\dfrac{\pi}{2}< \theta...
Here is my set up.
Let t = theta for short
tan(t) = 324/550
arctan(tan t) = arctan(324/550)
t = arctan(324/550)
Correct thus far?
Note: What does "not to scale" mean in other words?
I have a vector field which is originallly written as $$ \mathbf A = \frac{\mu_0~n~I~r}{2} ~\hat \phi$$ and I translated it like this $$\mathbf A = 0 ~\hat{r},~~ \frac{\mu_0 ~n~I~r}{2} ~\hat{\phi} , ~~0 ~\hat{\theta}$$(##r## is the distance from origin, ##\phi## is azimuthal angle and ##\theta##...
Perhaps I should ask this question in the math section of these forums.
But, I'm stumped and I don't think this equation is solvable?
Find theta given all the other variables:
After impact VCos(alpha) will be normal to the inclined, now i calculated for theta by using [ Tan(theta) = vCos(alpha)/vSin(alpha),. Tan(theta)= Cot(alpha) ]. I don't know how to solve further to get value of theta, according to book thta = alpha.
Hi,
I am working on a Boltzmann equation question and I know that the solution I am looking for is that:
log(nij/nji)=log(gij/gji)-Eij(eV)(5040/T)
The only thing I don't understand is why log(e-Eij/kt) = θ = 5040/T
From what I have read in textbooks, it is just a given, but I really want to...
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A certain football placekicker can kick the ball a distance d if she kicks it at 45°.
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Hello, I will post a picture below.
An optical device consists of two glass blocks of different indices of refraction, arranged as shown in the picture. The refractive index from air to medium 1 is 1.2, and the refractive index from medium 1 to medium 2 is 1.25
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I have a very simple question. Let's consider the theta term of Lagrangian:
$$L = \theta \frac{g^2}{32 \pi^2} G_{\mu \nu}^a \tilde{G}^{a, \mu \nu}$$
Investigate parity of this term:
$$P(G_{\mu \nu}^a)=+G_{\mu \nu}^a$$
$$P( \tilde{G}^{a, \mu \nu} ) =-G_{\mu \nu}^a$$
It is obvious. But what about...
What I've attempted to do is resolve vertically and horizontally:
T1sin(30)+T2sinΘ+T2=9g
T2cosΘ=T1cos30
After that... I'm completely stuck. Any help would be appreciated, I've spent so long on this I bet I'm just missing one simple thing.
Thanks in advance
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Homework EquationsThe Attempt at a Solution
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https://ibb.co/g6iKDQ
Calculate the magnitude of the force on cables 1 and 2 in the figure below if θ_1 = 55° and θ_2 = 35°.
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##\theta(\tau, A) = \sum\limits_{\vec{x}\in Z^{m}} e^{\pi i A[x] \tau } ##
##=\sum\limits^{\infty}_{n=0} r_{A}(n)q^{n} ##,
where ## r_{A} = No. [ \vec{x} \in Z^{m} ; A[\vec{x}] =n]##
where ##A[x]= x^t A x ##, is the associated quadratic from to the matrix ##A##, where here ##A## is positive...
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Mod note: Based on an attachment in a later post in this thread, the actual expression is
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Homework Statement
: https://www.physicsforums.com/posts/5610105/
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Say I have the integral of [ 1 / ( sqrt( 1 - x^2) ] * dx . Now I was told by many people in videos that I substitute x = sin theta, and this has me confused.
Wouldn't I need to substitute x = cos theta instead? as x = cos theta on the unit circle instead of sin theta?
Thanks in advance for...