My solution is very sketchy, but we want the math right. However, I've came to 2 thoughts that helped me get to the solution, and those are:
The only way that you can launch a ball at a velocity and have it be the same velocity two seconds later, is if it's already reached its maximum height...
I get it that nothing can travel faster than the speed of light in a vacuum, and that only massless particles can move that fast. Must move that fast. A photon, the massless boson that carries the electromagnetic force, moves as c, which is given by the inverse root of the electric permability...
I expanded it as shown above and got
##<v²> + <\bar v²> - 2<v><\bar v>## = ##v_{rms}^2 + \bar v^2 = \frac {3kT} m+\frac {8kT} {πm}##
I used ##<v> = 0## as the velocity is equally likely to be positive as it's likely to be negetive.
From the above I get the answer ##\frac {kT} m(3+\frac 8...
I know that for a single monoatomic gas with RMS velocity ##v_{rms}## , $$\frac 1 2mv_{rms}^2 = \frac 3 2k_bT$$ where ##m## is mass of a single molecule, ##k_b## is Boltzmann constant and ##T## is temperature of the gas.
For a mixture of gas, I know that the average kinetic energy after mixing...
I've been looking around and have gotten quite muddled about some concepts in special relativity. In the following I won't use four-vectors since I'd like to clear up the confusion first before adding more complexity!
The proper velocity/celerity is said to be ##\frac{dx}{d \tau} =...
I'm reading a book on Classical Mechanics (No Nonsense Classical Mechanics) and one particular section has me a bit puzzled. The author is using the Euler-Lagrange equation to calculate the equation of motion for a system which has the Lagrangian shown in figure 1. The process can be seen in...
I tried to calculate it by the way I know, i.e., setting the right hand side of the equation of motion to zero and getting
v² = 25g = 2500 (taking g =10)
=> v = 50m/s
But this answer is incorrect. How do I use the information of the initial velocity and why would it effect the terminal...
I determined 42m to be the hypotenuse so I used sine law to find the height of the incline, 10.87m. I used this height in the equation Ei=Ef, since they should be equal.
Ei=Ef
mgh=1/2mv^2 (at the start there is no kinetic energy, at rest. at the end there is only kinetic, no potential)...
We are given that ##v' = \frac{1}{10}v^2 - g##.
I tried using implicit differentiation so that ##v'' = \frac{1}{5}vv' = \frac{1}{5}v(\frac{1}{10}v^2-g)## and set this equal to 0. Hence we have 3 critical points, at ##v= 0##, and ##v = \pm \sqrt{10g}##.
Calculating ##v''(0)=-120##, we know the...
So I know that the total energy of the system initially is 775.5MeV, because the meson is at rest. Also by conservation of energy I know that the total final energy of the system is the same thing. I also know that the initial momentum of the system is 0 because the particle is at rest. This...
I used work energy theorem between initial top point and point x along the incline(downwards) i got the expression of v then diffrentiated it to get a maxima but it gives me a wrong ans which is 10/6 but the actual ans is 10/3 please tell me what i did wrong
I really cannot understand where this is going wrong...
Plugging in the constants, I get
vescape=Sqrt(2(6.67x10^-11)(5.976x10^24kg)/6378).
(6.67x10^-11)(5.976x10^24kg) gives me 3.99x10^14, and multiplied by 2 gives me 7.97x10^14.
7.97x10^14/6378=1.25x10^11.
The square root of 1.25x10^11 would...
I tried to solve this problem and this is what I could come through:
When the object is moving, the force acting on object is the frictional force, so, it got to be μmg.
So, F = ma and as F is μmg
μmg = ma
μg = a
So, to find out the magnitude of the initial velocity v given to the smaller...
Let us say that we have a stellar object so its total velocity is defined as
$$ v_{tot} = v_{pec} + V_{rec}$$
Where
$$V_{rec} = H_0r$$
and $$V(z) = \frac{cz}{1+z}[1+\frac{1}{2}(1-q_0)z - \frac{1}{6}(1-q_0-3q_0^2+j_0)z^2]$$
for small z.So my first question is what is the $z$ value here? Is...
The is a question about gravitational time dilation and escape velocity. As others have pointed out, you may use escape velocity to calculate gravitational time dilation in a gravitational field. (Interestingly, you can't use gravity to calculate gravitational time dilation, which makes...
A problem of an isolated system's velocity in different inertial systems, in special relativity
##\ \ \ \ \ ## In the inertial reference frame ##K##, the velocity of each component of an isolated system in ## x## direction is zero at a certain time.
##\ \ \ \ \ ## The inertial reference frame...
Hi, I am working on a kalman filter where my measurement equation involves "-g + v" , where g is in m/s^2 and v is velocity random walk given in m/s/sqrt(hr). Feels like a stupid question, but how can I transform the unit of velocity random walk so I can do the calculation correctly?
First i need the average linear velocity
100L/min =
0.1m3/min
0.00167m3/sec
Cross Sec Area = Pie r2
=pie(0.0175m)2
9.61x10-4 m2
0.0016m3/s / 9.61x10x-4m2
= 1.66m/s
But my notes say this should be 1.73 m/s
Once i have the average linear velocity i can calculate Re.
Help appreciated
I am designing a pitchback waterwheel for a head of 1m and flow rate of 20l/min. I've calculated that the theoretical power available to me is 3.27W and I know that the mechanical power I can extract is the product of torque and angular velocity but I'm struggling to find information on optimum...
So this question has something probably due to the conservation of angular momentum. I am able to find the moment of inertia about the pivot, which is :
$$\dfrac {1}{3}mL^{2}+\left( \dfrac {1}{12}ML^{2}+mL^{2}\right) =\dfrac {17}{12}ml^{2} $$
Now to find angular velocity when angle =0, how am I...
Pardon if the answers to my questions are obvious, because as usual I am trying to decipher everything on my own (as the material has not been taught to us quite well; then again it's graduate school). I just need someone to reassure me that I am understanding this correctly.
Say for example I...
Could I please ask for help regarding part (a) of this question:
If I get part (a) then part (b) will follow. So, here's my answer to part (a):
I'll be using the formula Elastic Potential Energy in a spring = (Yx^2)/(2a)
Where Y is the modulus of the spring, x the extension and a the natural...
For a cylinder rolling down an inclined plane, does the tangential velocity of a point a distance R from the axis of rotation equal the velocity of the center of mass?
First I calculated the y component of the initial velocity vector:
vy1 = 8.5 m/s * sin32
= 4.7 m/s
next the change in distance
Δd = d2 - d1
= 3.6m - 1.4m
= 2.2m
Then I put these numbers into the equation v2y^2 = v1y^2 + 2aydy
v2y^2 = (4.7 m/2)^2 + 2(-9.8 m/s^2)(2.2m)...
See the attached figure.
I understand that we look for the apparent transverse velocity v , for example through v = d/t (d - distance, t - time). The distance to the galactic nucleus is known as D. Though I am not sure how to read off the time from this figure.
Hello,
It has been a long time since I first looked at this, so thought I might ask for some help in clarifying this problem:
Is an equation of the form --> Velocity = (Distance) * (Trigonometric function) a valid one in physics?
If so, what is the relationship of trigonometric functions...
Hi gentlemen. My model is simple. Imagine, I watch a body which approaches me with velocity of w which value I can measure . I know that this a body has velocity v in a some reference system which aproaches me with same velocity of v. This velocity needs to be calculated (I can not mesure it)...
So after not being able to solve this problem I did some researching online. I was looking around and came across this video, where they give the following equations for solving for the final velocities of both balls:
v1f=((m1-m2)/(m1+m2))*v1i
v2f=(2m1/(m1+m2))*v1i
I plugged in my numbers and...
Hi there,
Just asking a logistics question since I want to be sure I am approaching this problem correctly.
My professor showed me an example of a bullet being fired from a barrel, given its initial velocity was 0. The change in time was 0.1 seconds. The mass of the bullet is 0.02 kg. The...
Hello All.
I am mentoring a high school student in my area with his class project for school. He has chosen he wants to launch an object (in our case, a softball) into a 5' diameter area. The idea is to build basically an oversized slingshot using an extension spring as the source of energy.
We...
My approach was that I consider the pressure of cross section A first
Pa= P + dgh
Now by writting Bernoulli's Equation between the cross-section A and the opening :
$$ Pa + 2dgh + 2dV^2/2 = Pb + 2dV'^2/2$$
Where Pb is the pressure of the opening which is equal to the atmospheric pressure...
I thought it would be a good idea to pretend that the walls are stationary and that each time the particle hits a wall, it gets a velocity addition of the velocity of the wall it’s hitting. Using this I ended up at the formula
V = initial velocity of particle + n(velocity of left wall) +...
I used the two equations above to solve for u_x and u_y and got u = 0.987c, where u_parallel = u_x and u_perpen = u_y. I wonder if I can use velocity four-vectors to solve this problem. Modify η'μ = Λμνην so we can use it for velocity addition?
I calculated the average velocity in a previous problem and got 1.146788991m/s over a time of 8.72s. I know I can’t use a_ave=(Vf-Vi)/(Tf-Ti) because I don’t know the final velocity and have no way to find it. Do I multiply average velocity by time?
Homework Statement: Jack can jump upwards a distance 1.4 meters when he is on the surface of the Earth. What is his initial velocity when he jumps?
Most of the time, however, Jack is in space. He is an asteroid miner: he looks for asteroids made out of useful metals. His job involves landing on...
I have a little question about converting Velocity formula that is derived as,
##\vec{V}=\frac{d\vec{r}}{dt}=\frac{dx}{dt}\hat{x}+\frac{dy}{dt}\hat{y}+\frac{dz}{dt}\hat{z}##
in Cartesian Coordinate Systems ##(x, y, z)##. I want to convert this into Polar Coordinate System ##(r, \theta)##...
I wrote Newton's equations for each body (I took ##x## as the axis aligned with the tension)
##m_1##:
##x)f*_1 -T_1+T_2=0##
Where ##f*_1=\omega ^2 r_1##
##m_2##
##x)f*_2 -T_2=0##
##x)f*_2=T_2##
Where ##f*_2=\omega ^2 r_2##
I wrote that ##T_2=1100 N## and solved for ##\omega##, and I got...
A) The slider experiments three forces, all of them are on the ##x## axis (considering ##x## axis as the axis aligned with the arm): Normal force (exerted by the support), elastic force and centrifugal force, which is ##m.(\omega^2 r)##
Elastic force is equal to
##Fe=-k \delta =-2 (R-2R)=2R##...
Hi all !
I wonder if I'm right.
(From : Fundamental University Physics, Volume 1 (Mechanics) - (Marcelo Alonso, Edward J.finn) Addison Wesley 1967)
This is my try:
* I have the Greek version of the book and there is no answer.Thanks.
Here were my assumptions: Energy and angular momentum are both conserved because the only force acting here is a central force. The initial angular momentum of this particle is ##L = mv_0b## and we can treat E as a constant in the homework equation given above. I solved for the KE (1/2 mv^2) in...
6.44 km * 1000 = 6440 m/2.51 m/s = 2565.737052 s = west time
av = (6440 m + - east distance)/(2565.737052 s + east time)
2565.737052 s + east time = total time
1.28 m/s * total time = (6440 m) - (0.495 m/s * east time)
1.28 m/s * (2565.737052 s + east time) = (6440 m) - (0.495 m/s * east...
I) For ##A##, the positition is ##\vec r=(0;V_0 . t;0)##.
For ##B##, we have ##\vec r_A=\vec r_B + \vec r_{A/B}##, but ##\vec r_{A/B}## is equal to zero because they have the same origin, so the position measured from ##A## is equal to the position measured from ##B##
II) For ##A##, velocity...
Addressing to electron as being rigid body that precesse is probably controversial. Are there any attempts to stick to that model and to calculate its quantize tangent velocity?
Is it possible to derive escape velocity say using momentum and force balance considerations? or using angular momentum consideration?
Namely, any other approach then energy consideration that utilizes gravitation potential energy and kinetic energy?
I have tried several things but I am a little uncertain if I’m thinking right so a little hint goes a long way. I think I have to use the law of conservation of momentum as the collision between the raindrops and the box is inelastic. But I am unsure how to set up the equation.