2.2.212 AP Calculus Exam problem find increasing interval

In summary, the given function is increasing on the interval [0, 10] only. The endpoints (-10 and 10) are not included in the interval because the slope at these points is 0, which is neither positive nor negative. The answer key may not have a correct answer because of the different interpretations of "increasing" function. According to the definition used by the AP, the closed interval [0, 10] is correct.
  • #1
karush
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212
Let f be the function given by $f(x)=300x-x^3$ On which of the following intervals is the function f increasing
(A) $\quad (-\infty,-10]\cup [10,\infty)$

(B) $\quad [-10,10]$

(C) $\quad [0,10]$ only

(D) $\quad [0,10\sqrt{3}]$ only

(E) $\quad [0,\infty]$
Steps
find first derivative to find min/max
$$y'=300-3x^2=3(100-x^2)=3(10+x)(10-x)$$
hence where $y'=0$ is at $-10,10$
an increasing interval of graph would have an positive slope so where
$$y'(0)=300$$
which is positive so the interval
$$[-10,10]\quad (B)$$

ok this was a little awkward to explain provided the answer is correct
but it was easy to get the zeros wrong due the highest power was the last term
 
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  • #2
karush said:
212
Let f be the function given by $f(x)=300x-x^3$ On which of the following intervals is the function f increasing
(A) $\quad (-\infty,-10]\cup [10,\infty)$

(B) $\quad [-10,10]$

(C) $\quad [0,10]$ only

(D) $\quad [0,10\sqrt{3}]$ only

(E) $\quad [0,\infty]$
Steps
find first derivative to find min/max
$$y'=300-3x^2=3(100-x^2)=3(10+x)(10-x)$$
hence where $y'=0$ is at $-10,10$
an increasing interval of graph would have an positive slope so where
$$y'(0)=300$$
which is positive so the interval
$$[-10,10]\quad (B)$$

ok this was a little awkward to explain provided the answer is correct
but it was easy to get the zeros wrong due the highest power was the last term
It looks good, but there is an error: the answer key doesn't have a correct answer!

Your analysis is good except at the endpoints. The slope of the function is 0 at the points x = -10 and x = 10. Since 0 is neither positive nor negative the endpoints cannot be part of your answer. The correct answer is (-10, 10).

-Dan
 
  • #3
topsquark said:
It looks good, but there is an error: the answer key doesn't have a correct answer!

Your analysis is good except at the endpoints. The slope of the function is 0 at the points x = -10 and x = 10. Since 0 is neither positive nor negative the endpoints cannot be part of your answer. The correct answer is (-10, 10).

-Dan

according to the definition of an increasing function used by the AP folks, the closed interval is correct ...

https://teachingcalculus.com/2012/11/02/open-or-closed/
 

FAQ: 2.2.212 AP Calculus Exam problem find increasing interval

What is the purpose of the 2.2.212 AP Calculus Exam problem?

The purpose of this problem is to test your understanding of finding increasing intervals in a given function. This is an important concept in calculus as it helps determine where a function is increasing or decreasing.

How do I approach solving this problem?

First, you need to find the derivative of the given function. Then, set the derivative equal to zero and solve for x to find the critical points. Next, create a number line and test values in between the critical points to determine if the function is increasing or decreasing. Finally, write your answer in interval notation.

What is the significance of finding increasing intervals in a function?

Finding increasing intervals helps us understand the behavior of a function. It tells us where the function is increasing, which is important for determining maximum values and optimization problems. It also helps us identify where the function is concave up or concave down.

Can I use a calculator to solve this problem?

Yes, you can use a calculator to find the derivative and solve for the critical points. However, you will need to show your work and explain your reasoning in order to receive full credit.

Are there any tips or tricks for solving this type of problem?

One helpful tip is to graph the original function and its derivative on the same coordinate plane. This can give you a visual representation of where the function is increasing or decreasing. Also, remember to check the endpoints of the given interval, as they can also be critical points.

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